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max2010maxim [7]
3 years ago
14

Need help desperately T~T

Mathematics
1 answer:
babunello [35]3 years ago
4 0
As you can see, angle 5 and angle 6 are supplementary.  And angle 5 and angle 3 are congruent because they are alternate interior angles.  

So it will be
x+2 = 180- x+3 
                         move x over from the right to the left
2x+2 = 183
                         move 2 over from the left to the right
2x = 181
                          divide by 2
x= 90.5

and angle 3 and angle 1 are vertical angles so they are congruent.  Using the angle 3 formula to solve for the answer:

90.5+3 =93.5

When angles are congruent, their measures are congruent, therefore, measure of angle 1 is 93.5
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Read 2 more answers
Addition and Subtraction of Rational
kvv77 [185]

Answer:

\frac{-1}{6}

Step-by-step explanation:

-\frac{5}{12}  + \frac{3}{12} = -\frac{2}{12}

-\frac{2}{12} = -\frac{1}{6}

which can also be written as:

\frac{-1}{6}

4 0
3 years ago
Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam
tigry1 [53]

Answer:

P(A) = \frac{30}{100}

P(B) = \frac{77}{100}

P(A\ n\ B) = \frac{22}{100}

P(A\ u\ B) = \frac{85}{100}

Step-by-step explanation:

Given

See attachment for proper format of table

n = 100 --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

Yes = 22 and No = 8

So, we have:

n(A) = Yes + No

n(A) = 22 + 8

n(A) = 30

P(A) is then calculated as:

P(A) = \frac{n(A)}{Sample}

P(A) = \frac{30}{100}

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

(1) = 22    (2) = 25 and (3) = 30

So, we have:

n(B) = (1) + (2) + (3)

n(B) = 22 + 25 + 30

n(B) = 77

P(B) is then calculated as:

P(B) = \frac{n(B)}{Sample}

P(B) = \frac{77}{100}

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

n(A\ n\ B) = 22

The probability is then calculated as:

P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}

P(A\ n\ B) = \frac{22}{100}

Solving (d): P(A u B)

This is calculated as:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)

This gives:

P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}

Take LCM

P(A\ u\ B) = \frac{30+77-22}{100}

P(A\ u\ B) = \frac{85}{100}

8 0
3 years ago
Please need help thank
babymother [125]

Answer:

1

Step-by-step explanation:

One member in the graph only went one time which is fewer than two times.

3 0
2 years ago
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