Answer:
6 tanks would required to fill in equal number of fishes in each tank.
Step-by-step explanation:
Given:
Number of Angel Fish = 12
Number of Sword tail fish =24
Number of guppies =30
We need to find the greatest number of tanks containing equal number of fishes.
Solution:
to find the greatest number of tanks containing equal number of fishes we will find the greatest prime factors of the number.
Multiples of 12 =
Multiples of 24 =
Multiples of 30 =
From above we get the the Greatest common prime factor =
Hence 6 tanks would required to fill in equal number of fishes in each tank.
1/6 - 6,12,18,24 (we counted by 6's, 2 times to get 12)
1/4 - 4,8,12,16 (we counted by 4's, 3 times to get 12)
12 is the LCD (Lowest Common Denominator) of the 2 fractions
*Now that we have the denominator, we need to find the numerator
1/12 - 1x2 (why 2? well because we had to count by 6's, 2 times to get 12)
1/4 - 1x3 (why 3? well because we had to count my 4's, 3 times to get 12)
2/12 and 3/12 is the answer
I hope you get it!!
You wold take 200.00 out of your balance and then multiply by 9.5% and that is your answer
volume = PI x r^2 x h
volume = 20,000
radius = 20 ft
20,000 = PI x 20^2 x h
20,000 = 3.14 x 400 x h
20,000 = 1256 x h
h = 20,000 / 1256 = 15.9235 feet
round answer as needed
RQ + QS = RS
Hope this helps!