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Nat2105 [25]
2 years ago
13

3 (x - 1) = 2x + 9 Is it A.infinite solutions B. One solution C. Zero solutions

Mathematics
1 answer:
kkurt [141]2 years ago
8 0

Answer:

its infinite solution

Step-by-step explanation:

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Help me. Please help me.
tekilochka [14]

Answer:

x=10 y=35 adjacent: AFE; CFD; BFC;BFD; AFB

Step-by-step explanation:

6 0
2 years ago
BIG IDEAS MATH
sveticcg [70]

Answer:

The required expression is \frac{y}{4}-3.

The value of the expression when y=20 is 2.

Step-by-step explanation:

Consider the provided phase.

3 less than the quotient of a number y and 4

The quotient of a number y and 4 can be written as: \frac{y}{4}

Now 3 less than the quotient of a number y and 4  can be written as:

\frac{y}{4}-3

Hence, the required expression is \frac{y}{4}-3.

Now evaluate when y=20.

Substitute y=20 in above expression.

\frac{20}{4}-3

5-3

2

Hence, the value of the expression when y=20 is 2.

3 0
3 years ago
Are some integers irrational
klemol [59]
What are the options?
4 0
3 years ago
Read 2 more answers
The systolic blood pressure (BP) of adults in the USA is nearly normally distributed with a mean of 121 and standard deviation o
Wittaler [7]

Answer:

Around 0.73% of adults in the USA have stage 2 high blood pressure

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 121 and standard deviation of 16.

This means that \mu = 121, \sigma = 16

Around what percentage of adults in the USA have stage 2 high blood pressure

The proportion is 1 subtracted by the p-value of Z when X = 160. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{160 - 121}{16}

Z = 2.44

Z = 2.44 has a p-value of 0.9927.

1 - 0.9927 = 0.0073

0.0073*100% = 0.73%

Around 0.73% of adults in the USA have stage 2 high blood pressure

5 0
3 years ago
Ppppppllease help meeeeee :)
nekit [7.7K]
I think is c because you just flipping the the letters and It should be the same answer ...but I’m not sure....
5 0
2 years ago
Read 2 more answers
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