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exis [7]
3 years ago
14

Jessie needs to get a picture blown up from a 4x6 standard print to a poster size frame she has. When she gets to the copy place

, she can only remember one of the frames measurements. She tells the worker that she knows for sure the frame is 16 in. wide, what would the heigh need to be?
Mathematics
2 answers:
Maru [420]3 years ago
7 0

Answer:

24

Step-by-step explanation:

4×4=16

6×4=24

the picture is being blown up ×4

ra1l [238]3 years ago
5 0
Answer:
24
Step-by-step explanation:
4×4=16
6×4=24
the picture is being blown up ×4
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Which country was Australia once a colony of?
Tema [17]
Austria was once a colony of Belgium
3 0
4 years ago
10. The perimeter of a regular nonagon is 162 inches. The apothem is 97.8 inches. Find the area.
Katen [24]

Answer:

The area of the regular nonagon is 7921.8 square inches.

Step-by-step explanation:

Geometrically speaking, the area of a regular polygon is determined by following area formula:

A = \frac{p\cdot a}{2} (1)

Where:

A - Area of the regular polygon, in square inches.

p - Perimeter, in inches.

a - Apothem, in inches.

If we know that p = 162\,in and a = 97.8\,in, then the area of the regular nonagon is:

A = 7921.8\,in^{2}

The area of the regular nonagon is 7921.8 square inches.

8 0
3 years ago
Guys please help i’m nearly on 23% and i need to get to 82%- giving brainlest
liberstina [14]
Add the numbers they equal 30 then u divide 30 by 2 since it’s an odd number and you get 15. so 15 is your answer
6 0
3 years ago
Read 2 more answers
HELP FAST, ILL GIVE BRAINIEST!!!!!
Lapatulllka [165]
The table is proportional, cause there all plus four.
-2 + 4 = 2
0 + 4 = 4
2 + 4 = 6
4 + 4 = 8

Hope it helps
3 0
3 years ago
An ornithologist has 4 bird feeders at separate locations. She wonders if birds are equally likely to visit each of the feeders.
Marianna [84]

Answer:

the x² test statistic 13.71

Option a) 13.71 is the correct answer.

Step-by-step explanation:

Given the data in the question;

Feeder                     1      2      3       4

Observed visits; o_i  60   90   92    58

data sample = 300

Expected e_i = 300 / 4 = 75

the x² test statistic = ?

X^2_{stat = ∑[ (o_i - e_i)²/e_i]

X^2_{stat = [ (60 - 75)² / 75 ] + [ (90 - 75)² / 75 ] + [ (92 - 75)² / 75 ] + [ (58 - 75)² / 75 ]

X^2_{stat = [ 3 ] + [ 3 ] + [ 3.8533 ] + [ 3.8533 ]

X^2_{stat = 13.7066 ≈ 13.71

Therefore, the x² test statistic 13.71

Option a) 13.71 is the correct answer.

7 0
3 years ago
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