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exis [7]
2 years ago
14

Jessie needs to get a picture blown up from a 4x6 standard print to a poster size frame she has. When she gets to the copy place

, she can only remember one of the frames measurements. She tells the worker that she knows for sure the frame is 16 in. wide, what would the heigh need to be?
Mathematics
2 answers:
Maru [420]2 years ago
7 0

Answer:

24

Step-by-step explanation:

4×4=16

6×4=24

the picture is being blown up ×4

ra1l [238]2 years ago
5 0
Answer:
24
Step-by-step explanation:
4×4=16
6×4=24
the picture is being blown up ×4
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The least common denominator (LCD) for 1/12 and 3/4 is b. 12
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Can someone please answer?<br><br> Which theorem is it?
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Answer:

  HL

Step-by-step explanation:

The triangles are right triangles, opening the possibility of using the special right-triangle congruence theorems.

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The HL theorem can be used to show the triangles are congruent.

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3 years ago
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I wanna pass this help me please-
Simora [160]

Answer:

C

Step-by-step explanation: hope this helps :)

5 0
3 years ago
I need help with my homework I did it but it is wrong.​
il63 [147K]

Answer:

  • π= 3V/(4r³)

Step-by-step explanation:

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3 0
3 years ago
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Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.
hram777 [196]

The center of mass is mathematically given as

\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \  \ \  x \in(0,1)$ \\\end

We calculate the total mass of the system.

\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}

Step 03: Calculate the moment of the system.

\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}

we calculate the center of mass.

\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}

Read more about the center of mass.

brainly.com/question/27549055

#SPJ1

8 0
2 years ago
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