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Valentin [98]
3 years ago
15

Find p (rolling 2 or 5) with one number cube

Mathematics
1 answer:
inysia [295]3 years ago
5 0

Answer:

Step-by-step explanation:

P(rolling 2 or 5)=2/6=1/3

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if theres a 32 ounce bottle of ketchup for $3.69 and a 44 ounce bottle for $5.00 which is the better deal per ounce?
RideAnS [48]

Answer:

Step-by-step explanation: Approx. cost of 1 ounce is $0.11.

So a 44 ounce bottle for $5.00 is a better deal.

6 0
3 years ago
Read 2 more answers
What is (n+2) / -8=-4
Travka [436]

\frac{n +2}{-8} =-4      Multiply -8 on both sides

\frac{n +2}{-8} (-8)=-4(-8)

n + 2 = 32       Subtract 2 on both sides

n + 2 - 2 = 32 - 2

n = 30

5 0
3 years ago
Vector u has a magnitude of 7 units and a direction angle of 330°. Vector v has magnitude of 8 units and a direction angle of 30
Dafna11 [192]
Keeping in mind that x = rcos(θ) and y = rsin(θ).

we know the magnitude "r" of U and V, as well as their angle θ, so let's get them in standard position form.

\bf u=
\begin{cases}
x=7cos(330^o)\\
\qquad 7\cdot \frac{\sqrt{3}}{2}\\
\qquad \frac{7\sqrt{3}}{2}\\
y=7sin(330^o)\\
\qquad 7\cdot -\frac{1}{2}\\
\qquad -\frac{7}{2}
\end{cases}\qquad \qquad v=
\begin{cases}
x=8cos(30^o)\\
\qquad 8\cdot \frac{\sqrt{3}}{2}\\
\qquad \frac{8\sqrt{3}}{2}\\
y=8sin(30^o)\\
\qquad 8\cdot \frac{1}{2}\\
\qquad 4
\end{cases}

\bf u+v\implies \left( \frac{7\sqrt{3}}{2},-\frac{7}{2} \right)+\left( \frac{8\sqrt{3}}{2},4 \right)\implies \left( \frac{7\sqrt{3}}{2}+\frac{8\sqrt{3}}{2}~~,~~ -\frac{7}{2}+4\right)
\\\\\\
\left(\stackrel{a}{\frac{15\sqrt{3}}{2}}~~,~~  \stackrel{b}{\frac{1}{2}}\right)\\\\
-------------------------------

\bf tan(\theta )=\cfrac{b}{a}\implies tan(\theta )=\cfrac{\frac{1}{2}}{\frac{15\sqrt{3}}{2}}\implies tan(\theta )=\cfrac{1}{15\sqrt{3}}
\\\\\\
\measuredangle \theta =tan^{-1}\left( \cfrac{1}{15\sqrt{3}} \right)\implies \measuredangle \theta \approx 2.20422750397203^o
8 0
3 years ago
Two automobiles leave the same city simultaneously and both head towards another city. The speed of one is 10 km/hour greater th
Veronika [31]

Answer:

5091 Km/hr and 505 km/hr

Step-by-step explanation:

Speed = Distance / Time

Let the speed of first automobile be 'x' and that of the second be 'y'

Since speed of one is 10 times greater than the other. therefore;

⇒ x = 10 y

also let time for faster automobile be 'T' and time for slower auto mobile be 't'

Since first arrive one hour earlier than second, therefore;

⇒ t = T + 1

⇒ For first automobile; x X T = 560 ; substituting for 'x' and 'T'. Therefore;

⇒ 10y (t+1) = 560

⇒ For Second automobile; y X t = 560

⇒ y = \frac{560}{t}

⇒ 10(\frac{560}{t})(t + 1) = 560

⇒ 5600 + \frac{5600}{t} = 560

⇒ 5600 - 560 =  -  \frac{5600}{t}

⇒ t = 1.11 hr

also ; T = 1.11 - 1 = 0.11 hr

Speed of 1st auto  = 560/0.11 = 5091 km /hr

Speed of 2nd auto = 560/1.11 = 505 km/hr

8 0
3 years ago
The table below shows the number of hours some college athletes in two states spend on indoor sports each week:
svet-max [94.6K]
Arrange the data set in ascending order:
State A:   4,   5,    6,   6,   7,    8,   9,  21,  25
State B: 10, 11, 12, 13, 14, 14, 15, 15,  16

5 number summary:
                             State A         State B
minimum                 4                  10
Q1                            5.5               11.5
median                    7                  14
Q3                          15                  15
maximum              25                 16
IQR                         9.5                  3.5

The box plot are not symmetric. The distance of the median from each Q1 and Q3 should be equal for the box plot to be symmetric.
5 0
3 years ago
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