Answer
so there are 7 singing acts and 5 comedy acts.
Step-by-step explanation:
Let x= number of singing acts.
Let y= number of comedy acts.
We will take x+y=12 as our first equation, as there are 12 shows in total. We will take 5x+3y=50 as our second equation as there are 50 total minutes, and singing acts are 5 mins and comedy acts are 3 mins.
We solve x+y=12
Y=-x+12
We know y=-x+12, so we will substitute that for the y in the second equation.
1. Substitute 5x+3(-x+12)=50
2. Distribute 5x-3x+36=50
3. Solve 2x+36=50
2x=14
X=7
Now that we have found x, we will find y by substitute the x in 5x+3y=50 with the value, 7, that we found for x.
5(7)+3y=50
35+3y=50
3y=15
Y=5
<span>20, 21, 22, 24, 25, 26, 27, 28, 30. hope that helped</span>
Answer:
(- 2, 15 ) and (2, 7 )
Step-by-step explanation:
Given the 2 equations
y = 3x² - 2x - 1 → (1)
2x + y = 11 → (2) ← subtract 2x from both sides
y = 11 - 2x → (3)
Substitute y = 3x² - 2x - 1 into (3)
3x² - 2x - 1 = 11 - 2x ( subtract 11 - 2x from both sides )
3x² - 12 = 0 ( add 12 to both sides )
3x² = 12 ( divide both sides by 3 )
x² = 4 ( take the square root of both sides )
x = ±
= ± 2
Substitute these values into (3) for corresponding values of y
x = - 2 : y = 11 - 2(- 2) = 11 + 4 = 15 ⇒ (- 2, 15 )
x = 2 : y = 11 - 2(2) = 11 - 4 = 7 ⇒ (2, 7 )