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Aleonysh [2.5K]
2 years ago
11

Hi can someone pls help me with this!!!

Mathematics
1 answer:
Eva8 [605]2 years ago
8 0

the domain is the x value (first number) and the range is the y value (second number)

(if a number appears more than once in the domain or range, like in number 1 you don't have to write it again.)

to graph the domain and range you just plot the points,

and to map them you have to put the x values in the first oval and the y values in the second, usually in order from smallest to largest.

then you have to draw arrows connecting each x value to the y value that was in the same pair. just like when writing down the domain/range, if a number comes up again you don't have to write it down again. instead, you might have two or more arrows connecting to the same  number.

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Can i get some help :
Charra [1.4K]

Answer:

b = \frac{7}{12}

Step-by-step explanation:

b + \frac{2}{3} = 1 \frac{1}{4} ← change to an improper fraction

b + \frac{2}{3} = \frac{5}{4}

Multiply through by 12 ( the LCM of 3 and 4 ) to clear the fractions

12b + 8 = 15 ( subtract 8 from both sides )

12b = 7 ( divide both sides by 12 )

b = \frac{7}{12}

5 0
2 years ago
Read 2 more answers
An advertising agency notices that approximately 1 in 50 potential buyers of a product sees a given magazine ad, and 1 in 8 sees
zheka24 [161]

Answer:

Probability = 0.12025

Step-by-step explanation:

P (Am) = 1/50 = 0.02       {Magazine ad}

P (At) = 1/8 = 0.125         {Television ad}

P (Am ∩ At ) = 1/100 = 0.01      {Both ads}

P (Am U At) = P (Am) + P (At) - P (Am ∩ At )

= 0.02 + 0.125 - 0.01

P (Am U At)  = 0.135       {Person sees either ad}

P (Am' ∩ At') = 1 - P (Am U At)

P (Am' ∩ At')  = 1 - 0.135 = 0.865      {Person sees none ad}

Prob (Purchase) = Prob (Purchase with ad) + Prob (purchase without ad)

P (P/ A) = 1/4 = 0.25 , P (P / A') = 1/10 = 0.1

P (P) = (0.25) (0.135) + (0.1) (0.865)

= 0.03375 + 0.0865

0.12025

7 0
2 years ago
X is all the following except<br> a term<br> a variable<br> a constant<br> an expression
lisov135 [29]

Answer: a constant

Step-by-step explanation:

A constant is a numerical expression like 2, 0,78 etc .

A variable is a alphabetical expression that vary like a,b,c,d,x,y,z.

An expression can consists of both numerical and alphabets and also any arithmetic expression like x, 2abc, 6a+2c etc

A term consist of either numbers and variables multiplied together or only numbers or variable like 2xy, x, 2ab etc.

X is all (a term, a variable , an expression) except a constant because a constant is a numerical expression.

6 0
3 years ago
The formula I = PRT is used to calculate the amount of simple Teresa earned. Solve this formula for T
Dmitrij [34]

To solve this formula for T, divide both sides of the original equation by PR:

  I         PRT

------ = ---------   =>    T = I / (PR)

PR        PR

Please note:  Because the formula I = PRT involves neither addition nor subtraction, the final formula for T cannot involve either addition nor subtraction.  That leaves:

T = I P/R

T= IPR

The second formula here is incorrect; we cannot solve I = PRT for T simply by rearranging the order of the variables.  This leaves T = I P/R as a possible answer, but this answer does not agree with my   T = I / (PR).  Please double check to ensure that you have copied down the four possible answers correctly.


8 0
3 years ago
In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen
Lesechka [4]

Step-by-step explanation:

Given - In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen concrete has a low value of thermal conductivity in order to minimize subsequent damage due to changing temperatures. Suppose two types of concrete, a graded aggregate and a no-fines aggregate, are being considered for a certain road. The table below summarizes data on thermal conductivity from an experiment carried out to compare the two types of concrete.

Type            ni                xi                  si

Graded       42           0.486            0.187

No-fines      42           0.359           0.158

To find - a. Formulate the above in terms of a hypothesis testing problem.

b. Give the test statistic and its reference distribution (under the null hypothesis).

c. Report the p-value of the test statistic and use it to assess the evidence that this sample provides on the scientific question of difference in mean conductivity of the two materials at the 5% level of significance.

Proof -

a.)

Hypothesis testing problem :

H0 : There is significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

H1 : There is no significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

b)

Test statistic :

Z = \frac{x_{1} - x_{2} }{\sqrt{\frac{s_{1} ^{2} }{n_{1}}  + \frac{s_{2}^{2} }{n_{2}} } }

Z = \frac{0.486 - 0.359 }{\sqrt{\frac{0.03496 }{42}  + \frac{0.02496 }{42} } }

Z = \frac{0.127 }{\sqrt{0.001468}}

Z = \frac{0.127 }{0.0377}

⇒Z(cal) = 3.3687

Z(tab) = 1.96

As Z (cal) > Z(tab)

So, we reject H0 at 5% Level of significance

p-value = 0.99962

Hence

There is significant difference in mean conductivity at the two materials.

5 0
2 years ago
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