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Norma-Jean [14]
2 years ago
11

The total source voltage in the circuit is 6-3i V. What is the voltage at the middle source

Mathematics
1 answer:
Bezzdna [24]2 years ago
5 0

Answer:

<em>The voltage at the middle source is</em> (2-4\mathbf{i})\ V

Step-by-step explanation:

<u>Voltage Sources in Series</u>

When two or more voltage sources are connected in series, the total voltage is the sum of the individual voltages of each source.

The figure shown has three voltage sources of values:

2 + 6\mathbf{i}

a + b\mathbf{i}

2 - 5\mathbf{i}

The sum of these voltages is:

V_t=4+a+(6+b-5)\mathbf{i}

Operating:

V_t=4+a+(1+b)\mathbf{i}

We know the total voltage is 6-3\mathbf{i}, thus:

4+a+(1+b)\mathbf{i}=6-3\mathbf{i}

Equating the real parts and the imaginary parts independently:

4+a=6

1+b=-3

Solving each equation:

a = 2

b = -4

The voltage at the middle source is (2-4\mathbf{i})\ V

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Flauer [41]

Option C: 1 is the simplification of the expression \left(-9 a^{3} b^{2} c^{10}\right)^{0}

Explanation:

The given expression is \left(-9 a^{3} b^{2} c^{10}\right)^{0}

We need to simplify the given expression.

<u>Simplification:</u>

To simplify the given expression, let us apply the exponent rule, a^{0}=1 where a \neq 0

Thus, the the exponent rule a^{0}=1 means that any value (except zero) to the power of zero is equal to one.

Thus, the expression \left(-9 a^{3} b^{2} c^{10}\right)^{0} becomes,

\left(-9 a^{3} b^{2} c^{10}\right)^{0}=1

Therefore, the simplified expression is 1

Hence, Option C is the correct answer.

8 0
3 years ago
Please helppp. I’ll mark the Brainlessly pleaseee help
Pepsi [2]

Step-by-step explanation:

The answer is the 2nd one, the denominator is greater than the numerator because if you add 2 AND x its gonna ge a bigger number than just x alone

4 0
3 years ago
What is the value of v? 45(v−7)=2 Enter your answer in the box.
netineya [11]
45(v - 7) = 2...divide both sides by 45
v - 7 = 2/45...add 7 to both sides
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A model for the density δ of the earth’s atmosphere near its surface isδ=619.09−0.000097pwhere p (the distance from the center o
natta225 [31]

Answer: 3.751*10^18kg

Step-by-step explanation:

δ =619.09−0.000097p....equa1 where p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter.

Calculating the density of air at 5km above earth surface

P = 5000m + 6370000m = 6.375*10^6m

δ = 619.09 -(.000097* 6.375*10^6)

δ = 0.715kg/m^3 = density

Since Mass = density*volume...equ2

To calculate volume of air around the spherical earth at height 5km

V = (4/3 pai R^3) - (4/3pai r^3) ...equation 3 where R =6.375*10^6m, r = 6.37*10^6

Substituting R and r in equation 2 to solve for volume of air

V = 1.085*10^21 - 1.08*10^21

V = 5.25*10^18m^3

Substituting δ and V into equation 2 to solve for mass of air

M = 0.715 * (5.25*10^18)

M = 3.751*10^18kg

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3 years ago
Max is thinking of a number, which he calls n. He adds 8 and then doubles the sum. What is Max's final number if his starting nu
Sonja [21]

Based on the given situation, Max final number if his starting number is 7 is -4.5

<h3 /><h3>Algebra</h3>

  • Unknown number = n

  • He adds 8

n + 8

  • then doubles the sum

2(n + 8)

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So,

2(n + 8) = 7

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2b = 7 - 16

2n = -9

n = -9/2

n = -4.5

Learn more about algebra:

brainly.com/question/4344214

#SPJ1

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2 years ago
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