Answer:
118-40=78
p either is less tham or equal to 78
the answer is c
Answer:
16π
Step-by-step explanation:
Given that:
The sphere of the radius = 


The partial derivatives of 

Similarly;

∴




Now; the region R = x² + y² = 12
Let;
x = rcosθ = x; x varies from 0 to 2π
y = rsinθ = y; y varies from 0 to 
dA = rdrdθ
∴
The surface area 



![= 2 \pi \times 4 \Bigg [ \dfrac{\sqrt{16-r^2}}{\dfrac{1}{2}(-2)} \Bigg]^{\sqrt{12}}_{0}](https://tex.z-dn.net/?f=%3D%202%20%5Cpi%20%5Ctimes%204%20%5CBigg%20%5B%20%5Cdfrac%7B%5Csqrt%7B16-r%5E2%7D%7D%7B%5Cdfrac%7B1%7D%7B2%7D%28-2%29%7D%20%5CBigg%5D%5E%7B%5Csqrt%7B12%7D%7D_%7B0%7D)

= 8π ( -2 + 4)
= 8π(2)
= 16π
Answer:
<h2> a. 1188 in.² </h2>
Step-by-step explanation:
Area of parallelogram is: A = B•H {H⊥B}
B = 36 in.
H = 33 in.
A = 36 in. • 33 in. = 1188 in.²
Answer:
AB is congruent is CD. (Last one)
Step-by-step explanation:
Hypotenuse leg is when the hypotenuse and ONE (you only need one, not two) leg of the triangle are congruent in a RIGHT triangle.
In the image, you already know that it is a right triangle and you know that the hypotenuse are congruent (Reflexive Prop) .You just need to know that the legs are congruent. So you choose which one has the legs congruent. The leg pairs that can be congruent are AD and CB or DC and AB. The only one that matches this is the last one