Answer/Step-by-step explanation:
Given:
m<EFH = (5x + 1)°
m<HFG = 62°
m<EFG = (18x + 11)°
Required:
1. Value of x
2. m<EFH
3. m<EFG
SOLUTION:
1. Value of x
m<EFH + m<HFG = m<EFG (angle addition postulate)
(5x + 1) + 62 = (18x + 11)
Solve for x using this equation
5x + 1 + 62 = 18x + 11
5x + 63 = 18x + 11
Subtract 18x from both sides
5x + 63 - 18x = 18x + 11 - 18x
-13x + 63 = 11
Subtract 63 from both sides
-13x + 63 - 63 = 11 - 63
-13x = -52
Divide both sides by -13
-13x/-13 = -52/-13
x = 4
2. m<EFH = 5x + 1
Plug in the value of x
m<EFH = 5(4) + 1 = 20 + 1 = 21°
3. m<EFG = 18x + 11
m<EFG = 18(4) + 11 = 72 + 11 = 83°
Answer:
x = 11
Step-by-step explanation:
Properties of a square,
1). Diagonal of a square bisect the opposite angles.
2). All interior angles of a square measure 90°.
From these properties,
m∠PQR = 90°
Since, diagonal QS bisects angle PQR,
m∠PQS = m∠RQS = 45°
(6x - 21)° = 45°
6x = 45 + 21
6x = 66
x = 11
Answer: y=-3x+7
Step-by-step explanation: The slope of a line that is perpendicular will always be the opposite ( change positive to negative) and the inverse. Since 1/3 is the slope we would change it to negative (-1/3) and flip it. The slope of the new line is -3. Your new equation is y=-3x+b. Now, plug in 4 for x and -5 for y. -5=-3(4)+b. B=7.
