Answer:

Step-by-step explanation:
Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

Next we factor what we can so we can further simplify the rest of the equation:

We can now cancel out (x+2)

Next we factor out even more:

We cancel out x-4 and reduce the 3 and 6 into simpler terms:

And we can now simplify it to:

Answer:
6yx2
Step-by-step explanation:
brackets means multiply hence -x×3y×-2x
Answer: transportation
Step-by-step explanation:
Answer:
There is a decreasing pattern the farther they are the less likely hit the target.
Step-by-step explanation:
Remember
(ab)/(cd)=(a/c)(b/d)
and

1kg=1000g=1*10^3g
hmm, I estimate, 4 of them
x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x=

=

=

a million has 9 zeroes
so 24 zeroes is alot that is a <span>septillion, so there are 2.5316 septillion uranium atoms in 1kg
a. 4
b. underestimate
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