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Temka [501]
4 years ago
14

A group. of 5 friends are sharing 2 pounds of trail mix.Write a division problem and a fraction to represent this situation.

Mathematics
1 answer:
sergejj [24]4 years ago
4 0
5 divided by 2 or 2/5
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I/3 is equivalent to
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2/6, 3/9, 4/12, 5/15, 6/18 ect.
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Statements that can be proven by a logical sequence of statements is called a(n)
laila [671]
A)Theorem. every theorem can be proved.
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4 years ago
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So i don't understand how factoring equations work in algebra 1
telo118 [61]

Answer:

this will help https://www.google.com/search?q=factoring+equations&oq=factoring+equations&aqs=chrome..69i57j0l6j69i61.464j0j7&sourceid=chrome&ie=UTF-8#kpvalbx=_w9Z8XvnVCsq7tgXx3SM51

Step-by-step explanation:

its in the video https://www.google.com/search?q=factoring+equations&oq=factoring+equations&aqs=chrome..69i57j0l6j69i61.464j0j7&sourceid=chrome&ie=UTF-8#kpvalbx=_w9Z8XvnVCsq7tgXx3SM51

7 0
4 years ago
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−4x+7y+5=0<br> x−3y=−5<br> ​ <br><br> How many solutions does the system have?
xeze [42]

   

Solution:  

Using Substitution Method:

-4x+7y=-5   (Equation 1)

x-3y=-5       (Equation 2)

get the value of x from Equation 2

x=3y-5     (Equation 3)  

Put the value of x from Equation 3 in Equation 1

-4(3y-5)+7y=-5

-4(3y)+20+7y=-5

-12y+7y=-5-20

-5y=-25

Negative sign on both sides cancels each other

y=25/5

y=5

Putting value of y in equation 3

x=3(5)-5

x=15-5

x=10

Therefore,   [x,y]=[10,5]

Using Elimination Method

-4x+7y=-5   (Equation 1)

x-3y=-5       (Equation 2)

Multiply equation 2 with -4 in order to eliminate the x term

-4(x-3y)=-5*4

-4x+12y=20     (Equation 3)

Adding Equation 1 and 3

-4x+7y=-5    

-4x+12y=20    

+    -     = -   (Change Of Sign with x and y terms)

-----------------

0x-5y = -25

-5y=-25

y=5  

Substituting y’s value is Equation 1

-4x+7(5)=-5

-4x+35=-5

-4x=-40

Cancellation of negative sign on both sides

x=40/4

x=10

[x,y]=[10,5]

3 0
3 years ago
Helllp please <br> Find the area of The following figures. Dimensions are in centimeters.
lukranit [14]

Answer:

\huge\mathfrak\red{Answer...} \\  \\ area \: of \: square \:  = side {}^{2} \\  \\  side = \: 6 \: cm   \\  \\ area \: of \: square \:  = 6 \times 6 \\  \\ area \: of \: square \:  = 36 \: cm.sq \\  \\ area \: of \: semicircle \:  = (1 \div 2)\pi \: r {}^{2}  \\  \\ radius = 2 \: cm \\  \\ area \: of \: semicircle = 6.28 \: cm.sq \\  \\ area \: of \: whole \: figure \:  = 36 + 6.28 \\  \\ area = 42.28 \: cm.sq

5 0
3 years ago
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