Please help me!! algebra 1!!

Help me with question 3. (It will be 33 points)

adoni [48]

Answer:

PartA

P = 4a

Part B

60 = P fence + 2a

60 = 6a

Part C

40

Step-by-step explanation:

We are building a fence so we are finding perimeter.

Adding the 3 sides

P = a+b+a

P = 2a+b

It is twice as long as it is wide

b= 2a

Replace in the equation for perimeter

P = 2a+(2a)

P = 4a

Part B

We know the perimeter is 60 for the entire backyard

The perimeter of the backyard is the fence plus the longer side

60 = P fence + b

Replacing b

60 = P fence + 2a

We know the equation for the perimeter of the fence is

60 = 4a + 2a

Combing like terms

60 = 6a

Part C

Solve for a and b

60 = 6a

Divide each side by 6

60/6 = 6a/6

10 =a

P fence = 4a

P = 4(10) = 40

5 0

3 years ago

When completely factored, 3x2−48 equals -

Svetlanka [38]

Answer:

Step-by-step explanation:

If you are asking what 3x2-48 is, then the rules of Pemdas would be relevant in this.

First we would multiply. So, 3 times 2 is 6.

Then, 6-48 is -42

5 0

3 years ago

Write an equation in which the quadratic expression 3x^2+6x-24 equals 0. Show the expression in factored form and explain what y

mr_godi [17]

Answer:

3x² + 6x - 24 = 0

(3x - 6)(x + 4) = 0

x = -4 , x = 2 when y = 0

Step-by-step explanation:

3x² + 6x - 24 = 0

(3x - 6)(x + 4) = 0

Means

3x - 6 = 0 ⇒ 3x = 6 ⇒ x = 6 ÷ 3 = 2

x + 4 = 0 ⇒ x = -4

The Parabola which represents the quadratic equation intersects x-axis at

points (2 , 0) and (-4 , 0)

5 0

3 years ago

PLEASE HELP MY HOMEWORK IS DUE 10 MIN!!!!!!!!!!!!!!!!! Now think about changing the triangle. What happens to angle Z if the unk

kompoz [17]

Answer:

Angle Z wil change because the side length is getting longer and tbe triangle would no longer fit the conditions

4 0

3 years ago

Find the exact values of the remaining five trigonometric functions of theta, suppose theta is an angle in the standard position

nexus9112 [7]

Answer:

$\sin(\theta)=60/61\text{ and } \csc(\theta)=61/60\\\cos(\theta)=11/61\text{ and } \sec(\theta)=61/11\\\tan(\theta)=60/11\text{ and } \cot(\theta)=11/60$

Step-by-step explanation:

So, we know that:

$\tan(\theta)=60/11\text{ and } 90\textdegree$

Since θ is in QI, this means that all of our trig ratios will be positive. Recall All Students Take Calculus. Since it's QI, we refer to A in All. The A tells us that all the ratios will be positive.

Now, let's figure out the remaining ratios knowing that all of them is positive. First, let's find the hypotenuse. Recall that tangent is the ratio of the opposite side to the adjacent side. So, we can use the Pythagorean Theorem to find the hypotenuse. So:

$a^2+b^2=c^2$