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andreyandreev [35.5K]
2 years ago
14

A student bikes 1/4 miles to school. After school, the student bikes 1/3 miles to a cousin’s house. Finally, the student bikes 7

/12 miles home. If the student bikes the same path every day, Monday through Friday, and does not bike on the weekends, how many miles does the student bike in 2 weeks? A11 2/3 miles B5 5/6 miles C2 1/3 D1 1/6 miles
Mathematics
1 answer:
lorasvet [3.4K]2 years ago
7 0

Answer:

1/4+1/3+7/12=1 1/6

1 1/6 times 10 =

11 4/6 or 11 2/3 A

Hope This Helps!!!

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Answer:

D ) 9

Step-by-step explanation:

From your  question, I assume that the difference of two squares would be d, since you could do this:

9 = 3 x 3

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Given the equation f(x) = (x 3)2 – 8, fill in the blanks:axis of symmetry: x =a1vertex:(a2, a3)number of real solutions: a4
Paha777 [63]
F ( x ) = ( x + 3 )² - 8 = x² + 6 x + 9 - 8 = x² + 6 x + 1
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Axis of symmetry is: x = -b/ 2 a, where: a = 1, b = 6 ( because it it in the form:
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Decide whether each table could represent a proportional relationship. If the
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Answer:

Step-by-step explanation:

If given tables in the picture show the proportional relationship,

Number of wheels (w) ∝ Number of buses (b)

w ∝ b

w = kb

Here, k = proportionality constant

k = \frac{w}{b}

Number of buses (b)           Number wheels (w)             Wheels per bus (\frac{w}{b})

          5                                           30                               \frac{30}{5}=6              

          8                                           48                               \frac{48}{8}=6

         10                                           60                               \frac{60}{10}=6

         15                                           90                               \frac{90}{15}=6

Here, proportionality constant is 6.

Similarly, If number of wheels (w) ∝ Number of train cars (t)

w = kt

Here, k = proportionality constant

k = \frac{w}{t}

Number of train cars(t)          Number of wheels(w)     Wheels per train car (\frac{w}{t})

              20                                        184                           \frac{184}{20}=9.2

              30                                        264                           \frac{264}{30}=8.8

              40                                        344                           \frac{344}{40}=8.6

              50                                        424                           \frac{424}{50}=8.48

Since, ratio of w and t is not constant, relation between number of wheels and number of train cars is not proportional.

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