6*5=30 30^2=900
900-14=886
Answer:
9 units
Step-by-step explanation:
Answer: b) 6
Step-by-step explanation:
Given : The illuminance of a surface varies inversely with the square of its distance from the light source.
i.e. for d distance and l luminance , we have
, where k is constant. (1)
If the illuminance of a surface is 120 lumens per square meter when its distance from a certain light source is 6 meters.
From (1), we have
(2)
For the distance (d) corresponds to the illuminance to 30 lumens per square meter , we have
Put value of k , we get
Then , the number of meters should the distance of the surface from the source be increased= 12 meters- 6 meters = 6 meters.
Answer:
-64/11
Step-by-step explanation: