Answer:
d. Since fertilizer is in both data sets and is positively correlated to both tree height and fruit yield, it is like that tree height and fruit yield are also positively correlated.
Step-by-step explanation:
The correlation refers to the relationship between two or more variables i.e how they are interrelated to each other. It can be positive, negative, perfect, etc
As we can see in the figure that in both the data sets the fertilizer contains the same values which depict that they are positively correlated with respect to the height of tree and fruit yield that derives that the height of tree and fruit yield is also positively correleated
Here positive correlation means that the two variables moving in a similar direction i.e if one variable increased so the other is also increased
Therefore the option d is correct
The perimeter is 2(length) + 2(width), so 2(x+5) + 2(x+4) = 42 m. In solving for x, you find 6. Plug 6 back into your length and width where x originally was, and you find your length to be 11m, and your width to be 10m. Hope this helps!
Answer:
The answer is option C.
<h3>-6, -5 2/5, -4 1/5</h3>
Step-by-step explanation:
The arithmetic sequence is given by
where n is the number of terms
<u>For</u><u> </u><u>the</u><u> first</u><u> </u><u>term</u>
n = 1
So we have
<u>For</u><u> </u><u>the</u><u> </u><u>fou</u><u>rth</u><u> term</u>
n = 4
<u>For</u><u> </u><u>the</u><u> </u><u>tenth</u><u> </u><u>term</u>
n = 10
Hope this helps you
Answer:
Probability that Jonas gets an orange is 1/4 and Beth gets a peach is 3/16.
Step-by-step explanation:
Here,
The total number of fruits n(S) = 3 + 4 + 4 + 2 + 3
= 16
The total number of oranges n(O) = 4
The total number of peas n(P) = 3
Now,
P(O) = n(O)/n(S)
= 4/16
= 1/4
Again,
P(P)= n(P)/n(S)
= 3/16
Answer:
18
Step-by-step explanation: 32/5.76
See how much 32 goes into 57
32 goes into 57: 1 time
1 times 32 is 32
32 - 57 is 25
Then bring down your 6 which now it will be 256
Now how much dose 256 go into 32
It would be 8: 8 x 32 is 256 - 256 = 0
So ur answer is 18
