C.48
110 students
- 42 photography
———
68
Now you must account for the fifteen who are in dual enrollment so 35-15=20
68
- 20
____
48
Answer:
My answer was deleted but it was between 4 and 6 weeks
Step-by-step explanation:
For this case we must simplify the following expression:
![\sqrt [3] {\frac {12x ^ 2} {16y}}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B%5Cfrac%20%7B12x%20%5E%202%7D%20%7B16y%7D%7D)
We rewrite the expression as:
![\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\sqrt[3]{\frac{4(3x^2)}{4(4y)}}=\\\frac{\sqrt[3]{3x^2}}{\sqrt[3]{4y}}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B4%283x%5E2%29%7D%7B4%284y%29%7D%7D%3D%5C%5C%5Csqrt%5B3%5D%7B%5Cfrac%7B4%283x%5E2%29%7D%7B4%284y%29%7D%7D%3D%5C%5C%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%7D%7B%5Csqrt%5B3%5D%7B4y%7D%7D%3D)
We multiply the numerator and denominator by:
![(\sqrt[3]{4y})^2:\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{\sqrt[3]{4y}*(\sqrt[3]{4y})^2}=](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%3A%5C%5C%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%7D%7B%5Csqrt%5B3%5D%7B4y%7D%2A%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%7D%3D)
We use the rule of power
in the denominator:
![\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{(\sqrt[3]{4y})^3}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{4y})^2}{4y}=](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%7D%7B%28%5Csqrt%5B3%5D%7B4y%7D%29%5E3%7D%3D%5C%5C%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B4y%7D%29%5E2%7D%7B4y%7D%3D)
Move the exponent within the radical:
![\frac{\sqrt[3]{3x^2}*(\sqrt[3]{16y^2}}{4y}=\\\frac{\sqrt[3]{3x^2}*(\sqrt[3]{2^3*(2y^2)}}{4y}=](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B16y%5E2%7D%7D%7B4y%7D%3D%5C%5C%5Cfrac%7B%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B2%5E3%2A%282y%5E2%29%7D%7D%7B4y%7D%3D)
![\frac{2\sqrt[3]{3x^2}*(\sqrt[3]{(2y^2)}}{4y}=\\\frac{2\sqrt[3]{6x^2*y^2}}{4y}=](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Csqrt%5B3%5D%7B3x%5E2%7D%2A%28%5Csqrt%5B3%5D%7B%282y%5E2%29%7D%7D%7B4y%7D%3D%5C%5C%5Cfrac%7B2%5Csqrt%5B3%5D%7B6x%5E2%2Ay%5E2%7D%7D%7B4y%7D%3D)
![\frac{\sqrt[3]{6x^2*y^2}}{2y}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B6x%5E2%2Ay%5E2%7D%7D%7B2y%7D)
Answer:
The total balance of the amount of money deposited into the account at the end of 4 years is $3194.76.
<h3>What is the total balance?</h3>
Simple interest rate is the interest that is paid only on the principal portion of the amount deposited. Compound interest is when interest is earned on the amount deposited and the interest accrued.
Compound value = amount deposited x (1 + interest rate) ^number of years
800(1.0125)^4 = $840.76
Future value of the account with simple interest = amount deposited + (principal x time x interest rate)
2200 + (2200 x 0.0175 x4) = $2354
Total value = 2354 + 840.76 = $3194.76
To learn more about compound interest, please check: brainly.com/question/26367706
#SPJ1
Answer:
c = (total points earned in best game / points per can knocked down)
c = 12
Step-by-step explanation:
Given that :
Points earned per knockdown = 7
Total points earned in best game = 84
Number of cans knocked down, c
c = (total points earned in best game / points per can knocked down)
c = 84/ 7
c = 12
