Question

A circular path 2feet wide has an inner diameter of 150 feet . How much farther is it around the outer edge of the path than around the inner edge?

Answer 1

The circumference of any circle is
diameter x pi.

Distance around the outside of the walk is (150+2+2) pi = 154 pi feet.

Distance around the inside of the walk is 150 pi feet.

Difference = 4 pi feet.

Same as if you strung a string around the Earth that was 2 feet off the surface everywhere.

The string would be 4pi feet longer than the Earth's circumference at the surface ... about 12.5 feet.

Answer 2

Answer: 12.56 feet

Step-by-step explanation:

Given: The width of the circular path= 2 feet

The inner diameter of circular path= 150 feet

Therefore, the inner radius of circular path=$\frac{150}{2}=75\ ft$

Now, the outer radius= 75+2=77 feet

We know that the circumference= $2\pi r$

Inner circumference= $2\pi 75=150\pi$

Outer circumference= $2\pi 77=154\pi$

The difference= $154\pi-150\pi=4\pi=4\times3.14=12.56\ feet$

Hence, the outer edge of the path is 12.56 feet farther than the inner edge