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Mnenie [13.5K]
2 years ago
11

Song lyric ideas please

Mathematics
2 answers:
Alex_Xolod [135]2 years ago
8 0
<h2>Tittle: The Way You Walk (The Generous, Kind And Fragrant Girl Song)</h2>

You find so many people are overgenerous

But you, you are mostly generous

I like the way you walk.

You do it like a mock.

I like the way you kick.

You do it like a bailiwick.

I like the way you snooze.

You do it like flews.

You find so many people are resigned

But you, you are mostly kind

I love the way you wear your hair,

Spreading your style everywhere.

You're like a style fountain.

Enough zazz for a whole mountain.

You find so many people are flagrant

But you, you are mostly fragrant

You're the perfect girl.

Leaving me in such a whirl.

You find so many people are chic

But you, you are mostly unique

Generous, kind and fragrant,

Unique and intelligent too,

Are the qualities of you

You find so many people are unintelligent

But you, you are mostly intelligent

g100num [7]2 years ago
3 0

Answer:

The crowd got me movin slow mo oouuuu

Step-by-step explanation:

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Let g' be the group of real matricies of the form [1 x 0 1]. Is the map that sends x to this matrix an isomorphism?
aliina [53]

Yes. Conceptually, all the matrices in the group have the same structure, except for the variable component x. So, each matrix is identified by its top-right coefficient, since the other three entries remain constant.

However, let's prove in a more formal way that

\phi:\ \mathbb{R} \to G,\quad \phi(x) = \left[\begin{array}{cc}1&x\\0&1\end{array}\right]

is an isomorphism.

First of all, it is injective: suppose x \neq y. Then, you trivially have \phi(x) \neq \phi(y), because they are two different matrices:

\phi(x) = \left[\begin{array}{cc}1&x\\0&1\end{array}\right],\quad \phi(y) = \left[\begin{array}{cc}1&y\\0&1\end{array}\right]

Secondly, it is trivially surjective: the matrix

\phi(x) = \left[\begin{array}{cc}1&x\\0&1\end{array}\right]

is clearly the image of the real number x.

Finally, \phi and its inverse are both homomorphisms: if we consider the usual product between matrices to be the operation for the group G and the real numbers to be an additive group, we have

\phi (x+y) = \left[\begin{array}{cc}1&x+y\\0&1\end{array}\right] = \left[\begin{array}{cc}1&x\\0&1\end{array}\right] \cdot \left[\begin{array}{cc}1&y\\0&1\end{array}\right] = \phi(x) \cdot \phi(y)

8 0
3 years ago
Find the height of a door on a scale drawing if the door is 2 meters tall and the scale is 1 centimeter = 4 meters. Round to the
larisa86 [58]
The door would be 0.5 cm tall

Answer: 0.5
7 0
3 years ago
How do I solve this equation
Anestetic [448]
-x - y = 8
2x - y = -1

Ok, we are going to solve this in 2 parts.  First we have to solve for one of the variables in one of the equation in terms of the other variable.  I like to take the easiest equation first and try to avoid fractions, so let's use the first equation and solve for x.

-x - y = 8      add y to each side
-x = 8 + y      divide by -1
x = -8 - y

So now we have a value for x in terms of y that we can use to substitute into the other equation.  In the other equation we are going to put -8 - y in place of the x.

2x - y = -1
2(-8 - y) - y = -1      multiply the 2 through the parentheses
-16 - 2y - y = -1      combine like terms
-16 - 3y = -1            add 16 to both sides
-3y = 15                   divide each side by -3
y = -5

Now we have a value for y.  We need to plug it into either of the original equations then solve for x.  I usually choose the most simple equation.

-x - y = 8
-x - (-5) = 8            multiply -1 through the parentheses
-x + 5 = 8                subtract 5 from each side
-x = 3                      divide each side by -1
x = -3

So our solution set is

(-3, -5)

That is the point on the grid where the 2 equations are equal, so that is the place where they intersect.

4 0
3 years ago
Ok y’all help ʜᴇʟᴘᴘᴘᴘᴘ ndjd d dndkdjdjdkdnfn dkcn
umka21 [38]

Answer:

C, 108 ft²

Step-by-step explanation:

To solve, we need to find the area of each of the shapes and then add them together.

The top rectangle's area: 8 * 3 = 24

The left triangle: 3 * 4 * 0.5 = 6

The middle rectangle: 8 * 4 = 32

The right triangle: 4 * 3 * 0.5 = 6

The bottom rectangle: 5 * 8 = 40

Add them all together.

24 + 6 + 32 + 6 + 40 = 108 ft²

Thus, the answer is C, 108 ft²

8 0
3 years ago
Read 2 more answers
Please help I am so confused lol. I’ll mark you the brainiest
ANTONII [103]

Answer:

Since the pentagon is regular, the line connecting the centre of the circle to the verticles (A,B,C,D,E) should inscribe an equal angle in them

You can see what I mean in the attachment

So to mark other points we follow the following steps

  1. Connect OA
  2. With OA as base, make angle of 72°. Say th new line is OB.
  3. Similarly, do for the rest of them
  4. This is a cyclic pentagon

Step-by-step explanation:

Hope this helps... Pls vote as brainliest

3 0
3 years ago
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