You can use a tangent:
![tangent=\dfrac{opposite}{adjacent}](https://tex.z-dn.net/?f=tangent%3D%5Cdfrac%7Bopposite%7D%7Badjacent%7D)
We have opposite = 17 and adjacent = x.
![\tan30^o=\dfrac{\sqrt3}{3}](https://tex.z-dn.net/?f=%5Ctan30%5Eo%3D%5Cdfrac%7B%5Csqrt3%7D%7B3%7D)
substitute:
cross multiply
multiply both sides by √3
![x(\sqrt3)(\sqrt3)=51\sqrt3](https://tex.z-dn.net/?f=x%28%5Csqrt3%29%28%5Csqrt3%29%3D51%5Csqrt3)
divide both sides by 3
![x=17\sqrt3](https://tex.z-dn.net/?f=x%3D17%5Csqrt3)
Use the Pythagorean theorem:
![y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34](https://tex.z-dn.net/?f=y%5E2%3D%2817%5Csqrt3%29%5E2%2B17%5E2%5C%5C%5C%5Cy%5E2%3D289%28%5Csqrt3%29%5E2%2B289%5C%5C%5C%5Cy%5E2%3D289%5Ccdot3%2B289%5C%5C%5C%5Cy%5E2%3D867%2B289%5C%5C%5C%5Cy%5E2%3D1156%5Cto%20y%3D%5Csqrt%7B1156%7D%5C%5C%5C%5Cy%3D34)
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Other method.
triangle.
The sides are in the ratio ![1:2:\sqrt3\to17:y:x](https://tex.z-dn.net/?f=1%3A2%3A%5Csqrt3%5Cto17%3Ay%3Ax)
Therefore
![17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3](https://tex.z-dn.net/?f=17%3A%282%5Ccdot17%29%3A%2817%5Csqrt3%29%5Cto17%3A34%3A17%5Csqrt3%5Cto%20x%3D34%2C%5C%20y%3D17%5Csqrt3)
Answer:
65
Step-by-step explanation:
only due .I am not very sure
A. x intercept is -8 ; y intercept is 4
Nikita's value is 4 times less than Bettina's value. I believe this is the answer.