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lilavasa [31]
3 years ago
13

-5x-/(3x-7)+4(3x-5)-(6x-9)

Mathematics
1 answer:
grigory [225]3 years ago
4 0

Answer:

-5x / 9x - 18

Step-by-step explanation:

= - 5x- / ( 3x - 7 ) + 4 ( 3x - 5 ) - ( 6x - 9 )

= applying rule : ( a ) = a

then, ( 3x - 7 ) = 3x - 7

= - 5x- / 3x - 7 + 4 ( 3x - 5 ) - ( 6x - 9 )

= applying the fraction rule : -a/b = a/b

= 5x / 3x - 7 + 4 ( 3x - 5 ) - ( 6x - 9 )

= -5x / 9x - 8. Answer!

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Roman55 [17]
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6 0
3 years ago
What is the solution to the inequality 13 x + 3 < 42 ?
zepelin [54]

Answer:

x < -15

Step-by-step explanation:

Here is the solution:

-3x-42 > 3

Add the numbers

-3x > 45

Divide both sides of the inequation by -3 and flip the inequality sign.

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6 0
3 years ago
What is 27/2 divided by 9/8
Katena32 [7]
\frac{27}{2} \div \frac{9}{8}

\frac{27}{2} \times \frac{8}{9}

\frac{3}{1} \times \frac{4}{1}

\frac{3 \times 4}{1 \times 1}

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12
7 0
4 years ago
Read 2 more answers
An arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up
Papessa [141]

Answer:

s(t)=-9.8t^2+49t+58.8

Step-by-step explanation:

We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.

We know that equation of an object's height t seconds after the launch is in form s(t)=-gt^2+v_0t+h_0, where

g = Force of gravity,

v_0 = Initial velocity,

h_0 = Initial height.

For our given scenario g=-9.8, v_0=49 and h_0=58.8. Upon substituting these values in object's height function, we will get:

s(t)=-9.8t^2+49t+58.8

Therefore, the function for the height of the arrow would be s(t)=-9.8t^2+49t+58.8.

6 0
4 years ago
Which property is demonstrated by this equation -7+7=0​
hram777 [196]

um....wut? What are you asking?

6 0
3 years ago
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