Answer:
2< AC<8
Step-by-step explanation:
For a triangle to exits sum of two sides must always be greater than the the third side
⇒ AC< AB+ BC =5+3=8 in
⇒AC<8 in
Also, the difference of the two sides must be smaller than the length of third side
⇒ AC> | AB-BC| = |5-3| =2
AC> 2 in
therefore, we can say 2< AC<8. Hence, AC can takes 3,4,5,6 values
Answer:
Inductive
Step-by-step explanation:
It is inductuctive as the reader is making an inference based off the information he or she is given
That is describing a rectangle! The only quadrilaterals with 4 right angles are squares and rectangles. Squares have equal sides but rectangles have one pair of parallel sides that is longer than the other. Hope this helps! If you get more than one answer and see it fit to do so, please mark me Brainliest Answer! Thank you!
So basically u keep the x on one side and the rest on the other. Get a common denominator. to get rid of the half u times both sides by 2.
hope this helps
C= 3b + 2d
Subtract 3b first.
C-3b = 2d
Divide by 2.
C-3b/2 = d
OR
C-3b
-------- = d Your final answer!
2
