Mike's age is five more than three times his sister's age. Mike is seventeen years old.
2 answers:
Answer:
The correct option is B) .
Step-by-step explanation:
Consider the provided information.
Mike's age is five more than three times his sister's age. Mike is seventeen years old.
Let Mike's sister age is x.
Five more than three times his sister's age can be written as:
Mike is seventeen years old.
Hence, the required equation is .
Thus, the correct option is B) .
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cost of one regular admission ticket = $ 10
cost of one senior citizen ticket = $ 5
<h3><u>Solution:</u></h3>Let "r" be the cost of one regular admission ticket
Let "s" be the cost of one senior citizen ticket
Given that,
<em><u>On day 1 you sold 30 Regular Admission tickets and 20 Senior Citizen tickets for a total of $400</u></em>
So we can frame a equation as:
30 Regular Admission tickets x cost of one regular admission ticket + 20 Senior Citizen tickets x cost of one senior citizen ticket = $ 400
30r + 20s = 400 ----- eqn 1
<em><u>Day two you sell 40 Regular Admission tickets and only 10 Senior Citizen tickets for a total of $450</u></em>
So we can frame a equation as:
40 Regular Admission tickets x cost of one regular admission ticket + 10 Senior Citizen tickets x cost of one senior citizen ticket = $ 450
40r + 10s = 450 ---- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "r" and "s"</u></em>
Multiply eqn 2 by 2
80r + 20s = 900 --- eqn 3
Subtract eqn 1 from eqn 3
80r + 20s = 900
30r + 20s = 400
(-) ---------------------
50r = 500
<h3>r = 10</h3>Substitute r = 10 in eqn 1
30r + 20s = 400
30(10) + 20s = 400
300 + 20s = 400
20s = 100
<h3>s = 5</h3><em><u>Thus we have:</u></em>
cost of one regular admission ticket = $ 10
cost of one senior citizen ticket = $ 5