Answer:
Given equation: ![x^2-8x =39](https://tex.z-dn.net/?f=x%5E2-8x%20%3D39)
when we complete the square , we take half of the value of 8 , then square it, and added to the left sides, we get;
![x^2-8x+4^2 = 39 +4^2](https://tex.z-dn.net/?f=x%5E2-8x%2B4%5E2%20%3D%2039%20%2B4%5E2)
∵8 is the value ![(\frac{8}{2})^2](https://tex.z-dn.net/?f=%28%5Cfrac%7B8%7D%7B2%7D%29%5E2)
Notice that, we add this both sides so that it maintains the equality.
then;
![x^2-8x+4^2 = 39 +4^2](https://tex.z-dn.net/?f=x%5E2-8x%2B4%5E2%20%3D%2039%20%2B4%5E2)
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Simplify:
![(x-4)^2 =55](https://tex.z-dn.net/?f=%28x-4%29%5E2%20%3D55)
The number must be added to complete the square is, ![4^2 = 16](https://tex.z-dn.net/?f=4%5E2%20%3D%2016)
Correct answer; A right angle
The value of constant a is -5
Further explanation:
We will use the comparison of co-efficient method for finding the value of a
So,
Given
![(x^2 - 3x + 4)(2x^2 +ax + 7)\\= x^2((2x^2 +ax + 7)-3x((2x^2 +ax + 7)+4(2x^2 +ax + 7)\\= 2x^4+ax^3+7x^2-6x^3-3ax^2-21x+8x^2+4ax+28\\Combining\ alike\ terms\\=2x^4+ax^3-6x^3+7x^2-3ax^2+8x^2-21x+4ax+28\\= 2x^4 +(a-6)x^3+(15-3a)x^2-(21-4a)x+28\\](https://tex.z-dn.net/?f=%28x%5E2%20-%203x%20%2B%204%29%282x%5E2%20%2Bax%20%2B%207%29%5C%5C%3D%20x%5E2%28%282x%5E2%20%2Bax%20%2B%207%29-3x%28%282x%5E2%20%2Bax%20%2B%207%29%2B4%282x%5E2%20%2Bax%20%2B%207%29%5C%5C%3D%202x%5E4%2Bax%5E3%2B7x%5E2-6x%5E3-3ax%5E2-21x%2B8x%5E2%2B4ax%2B28%5C%5CCombining%5C%20alike%5C%20terms%5C%5C%3D2x%5E4%2Bax%5E3-6x%5E3%2B7x%5E2-3ax%5E2%2B8x%5E2-21x%2B4ax%2B28%5C%5C%3D%202x%5E4%20%2B%28a-6%29x%5E3%2B%2815-3a%29x%5E2-%2821-4a%29x%2B28%5C%5C)
As it is given that
(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28
In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x
Comparing coefficient of x^3
![a-6 = -11\\a = -11+6\\a = -5](https://tex.z-dn.net/?f=a-6%20%3D%20-11%5C%5Ca%20%3D%20-11%2B6%5C%5Ca%20%3D%20-5)
So the value of constant a is -5
Keywords: Polynomials, factorization
Learn more about factorization at:
#LearnwithBrainly
Answer:
The maximum value of the equation is 1 less than the maximum value of the graph
Step-by-step explanation:
We have the equation
.
We can know that this graph will have a maximum value as this is a negative parabola.
In order to find the maximum value, we can use the equation ![x=\frac{-b}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%7D%7B2a%7D)
In our given equation:
a=-1
b=4
c=-8
Now we can plug in these values to the equation
![x=\frac{-4}{-2} \\\\x=2](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-4%7D%7B-2%7D%20%5C%5C%5C%5Cx%3D2)
Now we can plug the x value where the maximum occurs to find the max value of the equation
![y=-(2)^2+4(2)-8\\\\y=-4+8-8\\\\y=-4](https://tex.z-dn.net/?f=y%3D-%282%29%5E2%2B4%282%29-8%5C%5C%5C%5Cy%3D-4%2B8-8%5C%5C%5C%5Cy%3D-4)
This means that the maximum of this equation is -4.
The maximum of the graph is shown to be -3
This means that the maximum value of the equation is 1 less than the maximum value of the graph
For percent, you just move the decimal over two spaces to the right, and add the percent sign. In which that would be:
<em> .5%</em>
And for the fraction: Since the 5 is in the thousandths place, the fraction would equal to:
![\frac{5}{1000}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B1000%7D%20)
when simplafied:
![\frac{1}{200}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B200%7D%20)
~Hope this helped :)