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2 years ago

-2x^2+6x+7=2x-3 by quadratic formula

1 answer:

8 0

Answer: There is no real solution because the discriminant is negative. Nevertheless, x is √6 + 1 or 1 - √6. However, these solutions are not real because the discriminant is negative.

Explanation: The square root of a negative number is not a real number.

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Help me please with this math. find x and y

erastova [34]

Answer:X= 1.84. Y= 3.08

Step-by-step explanation:

-9x+8y =8 ............i

-8x+10y= -16........ii

Multiply equation I by 8

Multiply equation ii by 9

-72x+64y = 64 ..... iii

-72x+90y = 144 ..... iv

Subtract iv from iii

-26y = -80

y= 80/26

y= 3.08

Put the value of y in equation i

-9x+8y =8

-9x+8(3.08) = 8

-9x+24.64 = 8

-9x = 8-24.64

-9x=-16.64

Divide both side by 9

-9x/-9 = -16.64/-9

X= 1.84

3 0

3 years ago

find a number such that if 8 is subtracted from 9 times the number , the result is 6 more than twice the number

zheka24 [161]

Answer:

x=2

Step-by-step explanation:

let the number be x

9x-8=6+2x

9x-2x=6+8

7x=14

x=14/7

x=2

8 0

3 years ago

Let g(x)= -3x and h(x) x^2+3 Find (g°h)(0)

raketka [301]

<h3>Answer is -9</h3>

=================================

Work Shown:

(g°h)(x) is the same as g(h(x))

So, (g°h)(0) = g(h(0))

Effectively h(x) is the input to g(x). Let's first find h(0)

h(x) = x^2+3

h(0) = 0^2+3

h(0) = 3

So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.

Now let's find g(3)

g(x) = -3x

g(3) = -3*3

g(3) = -9

-------

alternatively, you can plug h(x) algebraically into the g(x) function

g(x) = -3x

g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)

g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3

g( h(x) ) = -3x^2 - 9

Next we can plug in x = 0

g( h(0) ) = -3(0)^2 - 9

g( h(0) ) = -9

we get the same result.

7 0

3 years ago

What go in the blanks?

Gnesinka [82]

Answer:NUMERATORS

Step-by-step explanation:

5 0

3 years ago

Two linear equations are shown. A coordinate grid with 2 lines. The first line is labeled y equals StartFraction one-third EndFr

Lorico [155]

Answer:

$(7,\frac{13}{3})$

Step-by-step explanation:

we have

<em>The equation of the first line</em>

$y=\frac{1}{3}x+2$ ------> equation A

<em>The equation of the second line</em>

$y=\frac{4}{3}x-5$ ------> equation B

Solve the system of equations by elimination

Multiply equation A by -4 both sides

$(-4)y=(-4)(\frac{1}{3}x+2)$

$-4y=-\frac{4}{3}x-8$ --------> equation C

Adds equation B and equation C

$y=\frac{4}{3}x-5\\-4y=-\frac{4}{3}x-8\\--------\\y-4y=-5-8\\-3y=-13\\y=\frac{13}{3}$

<em>Find the value of x</em>

substitute the value of y

$\frac{13}{3}=\frac{1}{3}x+2$

$\frac{1}{3}x=\frac{13}{3}-2$

Multiply by 3 both sides

$x=13-6$

$x=7$

therefore

The solution to the system of equations is the point $(7,\frac{13}{3})$

5 0

3 years ago

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