The cylinder because it has about 27.5 in.3 less wasted space than the prism
The area of the figure is 112 square inches.
Step-by-step explanation:
Step 1:
To calculate the value of the composite shape we first divide it into shapes that we know.
In this case, the composite shape consists of a rectangle and a parallelogram attached to it.
If we can calculate the individual areas of the two shapes we should be able to calculate the area of the composite shape.
Step 2:
The rectangle has a length of 22 cm and a width of 8.5 cm. The area of a rectangle is the product of its length and its width.
The area of the rectangle![= (length)(width)= (22)(8.5)=187.](https://tex.z-dn.net/?f=%3D%20%28length%29%28width%29%3D%20%2822%29%288.5%29%3D187.)
The area of the rectangle is 187 square cm.
Step 3:
The area of a parallelogram is the product of its base length and its height. The given parallelogram has a base length of 22 cm and a height of 7.5 cm.
The area of the parallelogram ![= (baselength)(height) = (22)(7.5) = 165.](https://tex.z-dn.net/?f=%3D%20%28baselength%29%28height%29%20%3D%20%2822%29%287.5%29%20%3D%20165.)
The area of the parallelogram is 165 square cm.
Step 4:
Now we calculate the area of the entire figure by adding the areas of the rectangle and the parallelogram.
Area of the figure ![= 187 + 165 = 352.](https://tex.z-dn.net/?f=%3D%20187%20%2B%20165%20%3D%20352.)
So the area of the figure is 352 square cm.
To find commision, you must multiply the price of the house times 6%, also known as 0.06.
355,000 x 0.06 = 21,300
The correct answer is "a"
Step-by-step explanation:
The data below is what was provided in the question and it is what I solved the question with
P(A1) = 0.23
P(A2) = 0.25
P(A3) = 0.29
P(A1 n A2 ) = 0.09
P(A1 n A3) = 0.11
P(A2 n A3) = 0.07
P(A1 n A2 n A3) = 0.02
a
P(A2|A1) = P(A1 n A2)/P(A1)
= 0.09/0.23
= 0.3913
We have 39.13% confidence that event A2 will occur given that event A1 already occured
b.)
P(A3 n A3|A1) = P(A2 n A3)n A1)/P(A1)
= 0.02/0.23
= 0.08695
We have about 8.7% chance of events A2 and A3 occuring given that A1 already occured.
C.
P(A2 u A3|A1)
= P(A1 n A2)u(A1 n A3)/P(A1)
= P( A1 n A2) + P(A1 n A3) - P(A1 n A2 n A3) / P(A1)
= (0.09+0.11-0.02)/0.23
= 0.18/0.23
= 0.7826
We have 78.26% chance of A2 or A3 happening given that A1 has already occured.
Answer:
1/2?
Step-by-step explanation:
3 boys over 6 girls. that would be 3/6. 3/6 is already 1/2. but its also simplest form.