Answer:
Step-by-step explanation:
A parallelogram is a quadrilateral with four sides.
Given parallelogram ABCD, to prove that opposite sides of the parallelogram are congruent.
Join D to B, the diagonal of the parallelogram which is also a traversal.
So that;
<ABD = <BDC (alternate angle property)
<BAC = <ACD (alternate angle property)
Also, diagonals;
/AC/ = /BD/ (reflexive property)
Then;
ΔABD = ΔCBD (Angle-Side-Angle, ASA, property)
Thus;
/AB/ ≅ /CD/ (corresponding sides of congruent triangles are congruent)
/BC/ ≅ /AD/ (corresponding sides of congruent triangles are congruent)
Therefore, the opposite sides of the parallelogram ABCD are congruent.
Answer:
a 
Step-by-step explanation:
In the hypotenuse, the leg values get multiplied by √2.
Extended Information on Right Triangles
30°-60°-90° Right Triangles
Hypotenuse → <em>2x</em>
Short Leg → <em>x</em>
Long Leg → <em>x√3</em>
45°-45°-90° Right Triangles
Hypotenuse → x√2
Two identical Legs → <em>x</em>
I am joyous to assist you anytime.
Y=m(x)+B is the slope intercept formula