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Gnoma [55]
3 years ago
14

Which shows the following expression after the negative exponents have been eliminated?

Mathematics
1 answer:
Sati [7]3 years ago
6 0
B. Negative exponent flip from denominator to numerator and numerator to denominator.
B is the second option.
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3 years ago
2 in 1
ollegr [7]
1)
2x^2 - 13x - 24 = 0;
the discriminant is : ( - 13 )^2 - 4 * 2 * ( -24 ) = 169 +  192 = 361 = 19^2 => we have two different rational-number solutions ;

2) 
[ -2( x + 2 ) - 3( x - 5 ) ] / [ ( x - 5 )( x + 2 ) ] < 0 <=>

( -5x + 11 ) /  [ ( x - 5 )( x + 2 ) ] < 0

We have 2 situations :
a)  - 5x + 11 < 0 and  ( x - 5 )( x + 2 ) > 0 => x∈ ( 11 / 5 , + oo ) and x∈( -oo, - 2 )U
( 5 , + oo ) => x∈( 5, +oo);
b)   - 5x + 11 >  0 and  ( x - 5 )( x + 2 ) <  0 => x∈(-oo, 11/5) and x∈( -2, 5 ) =>
x∈( -2, 11/5 );

Finally, x∈ U (-2, 11 / 5 ) U ( 5, +oo).
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What is the answer to 23?
baherus [9]
The answer is 66 sorry if incorrect
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