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DanielleElmas [232]
3 years ago
12

How are transformations and functions related

Mathematics
1 answer:
Digiron [165]3 years ago
3 0

Answer:

In general, transformations are used to turn one function into another one. For example if I have a line f(x) = 2x + 3 and I want to turn it into a line that passes through (0,6) and has the same slope, I can write a new function which moves (translates) f(x) vertically 3 units: g(x) = f(x) + 3. Substituting for f(x) will show you what happened in the transformation - g(x) = (2x + 3) + 3 = 2x + 6.

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Calculate the slope of the line.Please help!!
vladimir2022 [97]
The slope is 2/3 you’re welcome :)
5 0
3 years ago
Solve by using substitution.<br><br> =3−8<br><br> =−4
garik1379 [7]

Answer:

I'm going to assume that you meant y=3x-8 and y=-4

This means that you would substitute -4 into the spot of y which gives you -4=3x-8. Once solved you would receive x=4/3.

Hope I helped have a nice day :)

3 0
2 years ago
Simplify (7^6)^2 .....................................
marysya [2.9K]

Answer:

13,841,287,201

Step-by-step explanation:

simply the parenthesis:

7^6 or 7 times itself 6 times: 7x7x7x7x7x7

which equals 117,649 and then multiply that number by itself

117,649x117,649 and you should get 13,841,287,201

5 0
3 years ago
Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th
DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0
3 years ago
Please help I don't understand i'm in the lowest class?
Anna71 [15]

Answer:

Step-by-step explanation:

6 0
2 years ago
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