Find the next two terms in the pattern 100,98,94,88,80…

Mathematics

1 answer:

olga_2 [115]2 years ago

5 0

Answer:

its 70 and 58

Step-by-step explanation:

The pattern: -2, -4, -6, -8, -10, -12...

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If f(x)=(1/8)(8^x) what is f(3)? A. 1/512 B. 1/64 C. 512 D. 64

cestrela7 [59]

Hi there!

Let's solve this problem step by step!
$f(x) = \frac{1}{8} (8 {}^{x})$

To find f(3) we must substitute x = 3 into the formula.
$f(3) = \frac{1}{8} (8 {}^{3} )$

Now we use PEMDAS (Parenthesis, exponents, multiply, divide, add, subtract) to find our answer.

Work out the exponents inside the parenthesis first.
$f(3) = \frac{1}{8} \times 512$

And finally multiply.
$f(3) = \frac{1}{8} \times \frac{512}{1} = \frac{512}{8} = 64$

Hence, the answer is D. 64.
~ Hope this helps you!

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3 years ago

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You'll notice that 36's prime factors had 2 even, and none other had an even number of even prime factors. Therefore, if you have an even number of even prime factors, your square root will be rational given the data

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3 years ago

Please answer this Hope you get along I report What to answer

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What the hel you expect us to do all that for 5 kids points? Go ask you mom to do that for you. If you're asking US to do that, then it has to be 40 or 50 points.

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3 years ago

Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).

Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5$

well then therefore

$\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}$

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}$

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A cube’s lengths are all the same, so any answer to x^3 which is larger than 216
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