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vesna_86 [32]
2 years ago
5

5) Naomi is sewing some clothing. She has 53 yards of fabric to use. She

Mathematics
1 answer:
EleoNora [17]2 years ago
6 0

The inequality that represents the number of each type of fabric that Naomi has is:

9x+16y \leq 53

Let the number of short-sleeved shirts she made be x

Let the number of long-sleeved shirts she made be y

Length of clothes used to make a short-sleeved shirt = 9 yards

Length of clothes used to make a long-sleeved shirt = 16 yards

Length of short-sleeved shirts made = 9x

Length of long-sleeved shirts made = 16y

Total length of fabric used = 53 yards

The inequality that represents the number of each type of fabric that Naomi has is:

9x+16y \leq 53

Learn more on inequality here: brainly.com/question/15269537

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A piece of cardboard is 13 inches by 26 inches. A square is to be cut from each corner and the sides folded up to make an open-t
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Answer:

Hence the maximum possible volume will be the 778.53 c.c

Step-by-step explanation:

Given:

A rectangle with 13 x 26 dimensions

And corners are cut to form side squares.

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Maximum possible volume for box

Solution :

Consider a rectangle of 13 x 26 dimension with and side of square  at corner be x.

(Refer the attachment)

Now,

Formulating the volume equation for the box

So corner square sides we are going to fold up which makes height of the box

and remaining part will be length and breadth

As shown in fig,

Length=26-x

breadth=13-x

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To get maximum volume differentiate the above equation,

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V(x)=x^3-39x^2+338x\\

V'(x)=3x^2-78x+338

V''(x)=6x-78

Now ,Solve the Quadratic Equation to get x values,

3x^2-78x+338=0

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x=[78±Sqrt[(78)^2-4*338*3)]/2*3

x=[78±Sqrt(3028)]/6

x=[78±55.027]/6

x=78+55.027/6 or x=78-55.027/6

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Use these values in 6x-78 to know which value posses the max and min value for the function.

So when x=22.17

6x-78=6*22.17-78

=55.02>0  i.e function will have minimum value .

When x=3.8288

6*3.8288-78

=-55.0272<0 i.e. Function will have maximum value

Now, the function will defines the maximum volume

V(x)=x^3-39x^2+338x

V(x)=3.8288^3-39*(3.82883)^2+338*3.8288

V(x)=56.13-571.73+1294.13

V(x)=778.53 C.C

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