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faltersainse [42]
3 years ago
8

Solve for the roots in simplest form by completing the square x^2-12x+20=0

Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0

Answer:

x = 10 or x = 2

Step-by-step explanation:

Solve for x:

x^2 - 12 x + 20 = 0

Hint: | Solve the quadratic equation by completing the square.

Subtract 20 from both sides:

x^2 - 12 x = -20

Hint: | Take one half of the coefficient of x and square it, then add it to both sides.

Add 36 to both sides:

x^2 - 12 x + 36 = 16

Hint: | Factor the left hand side.

Write the left hand side as a square:

(x - 6)^2 = 16

Hint: | Eliminate the exponent on the left hand side.

Take the square root of both sides:

x - 6 = 4 or x - 6 = -4

Hint: | Look at the first equation: Solve for x.

Add 6 to both sides:

x = 10 or x - 6 = -4

Hint: | Look at the second equation: Solve for x.

Add 6 to both sides:

Answer: x = 10 or x = 2

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Answer:

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Step-by-step explanation:

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\bold{Answer}

\boxed{\bold{-20x^6+12x^4-4x^3+8x^2}}

\bold{Explanation}

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\bold{------------------}

  • \bold{Distribute \ Parenthesis}

\bold{\left(-4x^2\right)\cdot \:5x^4+\left(-4x^2\right)\left(-3x^2\right)+\left(-4x^2\right)x+\left(-4x^2\right)\left(-2\right)}

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\bold{-20x^6+12x^4-4x^3+8x^2}

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