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larisa [96]
2 years ago
6

Solve the following automotive-services problems based on the examples shown previously. Choose the correct answer.

Mathematics
2 answers:
Radda [10]2 years ago
7 0
Transmission must be in third gear as both are running at the same speed ! so third gear !!!
blondinia [14]2 years ago
7 0

Answer:

Transmission is in 3rd gear.

Step-by-step explanation:

It's given in the question that in first gear, or low gear, an automobile's engine runs about 3 times as fast as the drive shaft.

In 2nd gear the engine runs about 1.6 times faster than the shaft drive.

But in third or higher gear the engine runs at the same speed as the drive shaft.

Engine speed = Drive shaft speed = 2400 r.p.m.

Therefore, transmission is in 3rd gear.

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Calculate the slope of the line for Graph B.
Alex

Answer:

-1

Step-by-step explanation:

rise = -2

run = 2

Slope = rise / run

= -2/2 = -1

Since also the angle made by the line and x axis in anti clockwise direction is > 90° the slope will be-ve .

7 0
2 years ago
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Jamal runs the bouncy house at a festival. The bouncy house can hold a maximum of 1200 pounds at one time. He
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Sorry I really need point but I wish you good luck!
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Three investors own a company. One partner owns One-fourthof the company, while the second partner owns Two-fifths of the compan
Lelechka [254]

Answer:

7/20

Step-by-step explanation:

2/5 = 8/20

1/4 = 5/20

20/20 - 13/20 = 7/20

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3 years ago
How many different ways can 5 identical tubes of tartar control toothpaste, 3 identical tubes of bright white toothpaste, and 4
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3 years ago
The circumference of a sphere was measured to be 82 cm with a possible error of 0.5 cm.
Nat2105 [25]

Answer:

A) Maximum error = 170.32 cm³

B)Relative error = 0.0575

Step-by-step explanation:

A) Formula for circumference is: C = 2πr

Differentiating with respect to r, we have;

dC/dr = 2π

r is small, so we can write;

ΔC/Δr = 2π

So, Δr = ΔC/2π

We are told that ΔC = 0.5.

Thus; Δr = 0.5/2π = 0.25/π

Now, formula for Volume of a sphere is;

V(r) = (4/3)πr³

Differentiating with respect to r, we have;

dV/dr = 4πr²

Again, r is small, so we can write;

ΔS/Δr = 4πr²

ΔV = 4πr² × Δr

Rewriting, we have;

ΔV = ((2πr)²/π) × Δr

Since C = 2πr, we now have;

ΔV = (C²/π)Δr

ΔV will be maximum when Δr is maximum

Thus, ΔV = (C²/π) × 0.25/π

C = 82 cm

Thus;

ΔV = (82²/π) × 0.25/π

ΔV = 170.32 cm³

B) Formula for relative error = ΔV/V

Relative error = 170.32/((4/3)πr³)

Relative error = 170.32/((4/3)C³/8π³)

Relative errror = 170.32/((4/3)82³/8π³)

Relative error = 170.32/2963.744

Relative error = 0.0575

3 0
2 years ago
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