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irakobra [83]
3 years ago
14

Need help with trigonometry, due in two daysWill mark as brainliest if helpful

Mathematics
1 answer:
Sati [7]3 years ago
6 0

\boxed{\sf tan\theta=\dfrac{Perpendicular}{Base}}

  • Perpendicular=27.8ft
  • Base=19.6ft

Now

\\ \tt\hookrightarrow tanx=\dfrac{27.8}{19.6}

\\ \tt\hookrightarrow tanx=\dfrac{13.9}{9.8}

\\ \tt\hookrightarrow tanx=1.418

\\ \tt\hookrightarrow \underline{\boxed{\bf tanx=1.42}}

Value of x

\\ \tt\hookrightarrow x=tan^{-1}(1.42)

\\ \tt\hookrightarrow x=54.8°

Hope It helps

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