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Assoli18 [71]
3 years ago
6

(Math Help Quick Lots of points please thanks)

Mathematics
2 answers:
Elden [556K]3 years ago
8 0

Answer:

E = {0, 1, 2, 3)

Step-by-step explanation:

  • <u>Integer</u>: a number with no decimal or fractional part, from the set of negative and positive numbers, including zero
  • < means less than
    > means more than

E = {0, 1, 2, 3)

RUDIKE [14]3 years ago
4 0
  • E={y|y is an integer and -1<y<4}

Now here value of y is

\\ \tt\hookrightarrow y\in(-1,4)

\\ \tt\hookrightarrow E=\{0,1,2,3\}

Done

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Solve the following rational equation for x 5/8 = x/12 <br> x=
kramer

Answer: x, 5/8=x^2/12

Step-by-step explanation: Simplify the matrix.

3 0
2 years ago
hunter has a total of $9.60 in dimes and nickels. let n be the number of nickels and d be the number of dimes. hunter knows ther
Vladimir79 [104]

9514 1404 393

Answer:

  (n, d) = (56, 68)

  Hunter has 56 nickels and 68 dimes.

Step-by-step explanation:

The equations can be solved by using the second equation to substitute for d in the first equation.

  10(n +12) +5n = 960

  120 +15n = 960 . . . . . . . eliminate parentheses

  15n = 840 . . . . . . . . . . . . subtract 120

  n = 56 . . . . . . . . . . . . . . . divide by 15

  d = 56 +12 = 68 . . . . . . . find d

The solution is n = 56, d = 68. This means Hunter has 56 nickels and 68 dimes.

_____

The meaning of the solution comes from the definitions of the variables.

8 0
3 years ago
Why is -3 an integer?
Lera25 [3.4K]
For example, -7 is an integer<span>, so it is also a rational and a real number. The square root of 2 is an irrational number, so it is also a real number.</span>
5 0
3 years ago
Read 2 more answers
Bridget needs an actor actor is offering her services for initial $250 in addition to $40 per day actor beers offering her servi
Neporo4naja [7]

Answer:it will take 9 days for both actors to charge the same amount.

Step-by-step explanation:

Let x represent the number of days it will take the cost of hiring either actor A or actor B to be the same.

Let y represent the cost of hiring actor A for x days.

Let z represent the cost of hiring actor B for x days.

Actor A is offering her services for initial $250 in addition to $40 per day. It means that

y = 250 + 40x

Actor B is offering her services for an initial $160 in addition to $50 per day. It means that

z = 160 + 50x

To determined the number of days when both costs would be the same, we would equate equation y to equation z. It becomes

250 + 40x = 160 + 50x

50x - 40x = 250 - 160

10x = 90

x = 90/10 = 9

4 0
3 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So \mu = 373, \sigma = 67

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So n = 5, s = \frac{67}{\sqrt{5}} = 29.96

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 373}{29.96}

Z = 1.23

Z = 1.23 has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So \mu = 526, \sigma = 107

B) What is the probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes?

So n = 5, s = \frac{107}{\sqrt{5}} = 47.86

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 526}{47.86}

Z = -2.42

Z = -2.42 has a pvalue of 0.0078.

So there is a 1-0.0078 = 0.9922 = 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

7 0
3 years ago
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