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2 years ago

Z(0,-5) Go left 5, up right, and down 3.

Mathematics

1 answer:

Alex73 [517]2 years ago

7 0

Answer:

(-4,-7)

Step-by-step explanation:

plz mark brainliest

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If (-2,11)and(9,22) are two anchor points on the trend line, then find the equation of the line

Elza [17]

Answer:

The equation of the line is $y=x+13$

Step-by-step explanation:

step 1

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

(-2,11) and (9,22)

substitute

$m=\frac{22-11}{9+2}$

$m=\frac{11}{11}$

$m=1$

step 2

Find the equation in slope intercept form

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$m=1$

$point\ (-2,11)$

substitute in the equation and solve for b

$11=(1)(-2)+b$

$11=-2+b$

Adds 2 both sides

$b=11+2\\b=13$

The equation of the line is

$y=x+13$

4 0

3 years ago

The graph shows the total monthly sales as a function of the number of cake tiers. Which statement is true?

liraira [26]

as tiers increases, sales increases

since there seems to be no assemtote (horizontal or vertical), As the number of cake tiers increases without bound, the total monthly sales increase without bound.

answer is 3rd option

6 0

3 years ago

Read 2 more answers

Y=1/2x-3<br>Need it graphed <br>only need the x and y intercept

MaRussiya [10]

Here u gooo hope this helps

8 0

3 years ago

Read 2 more answers

Help Please! Easy Question I will mark brainest :)

Mashcka [7]

6. K=4
7. N=11
8. C=2
9. R=7
10. R=4
11. Y=1
12. R=7
13. N=7

3 0

3 years ago

A population of values has a normal distribution with μ = 247 and σ = 62.2. You intend to draw a random sample of size n = 16. (

nadya68 [22]

Answer:

a) $z = \frac{295.2-247}{62.2}=0.772$

And using the normal distribution table or excel we got:

$P(Z>0.772) = 1-P(Z$

b) $z = \frac{295.5 -247}{\frac{62.2}{\sqrt{16}}}= 3.119$

And we can use the normal standard table or excel in order to find the probability and we got:

$P(z>3.119) =1-P(Z$

Step-by-step explanation:

For this case we know that the random variable of interest is normally distributed with the following parameters:

$X \sim N (\mu = 247, \sigma =62.2)$

Part a

We want to find this probability:

$P(X>295.2)$

And we can use the z score formula given by:

$z = \frac{X-\mu}{\sigma}$

Replacing we got:

$z = \frac{295.2-247}{62.2}=0.772$

And using the normal distribution table or excel we got:

$P(Z>0.772) = 1-P(Z$

Part b

We select a random sample of size n = 16 and we try to find this probability:

$P(\bar X >295.2)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{295.5 -247}{\frac{62.2}{\sqrt{16}}}= 3.119$

And we can use the normal standard table or excel in order to find the probability and we got:

$P(z>3.119) =1-P(Z$

8 0

3 years ago