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3 years ago

6

What is the probability of losing 6 times in a row playing Heads or Tails flipping a coin?

2 answers:

slava [35]3 years ago

6 0

The probability of losing per flip is 1/2. Multiply 1/2 by itself 6 times since the condition is asking for the probability for the person to lose 6 times in a row. 1/2 * 1/2 * 1/2 * 1/2 * 1/2 * 1/2 = 1/64. The answer is 1/64.

charle [14.2K]3 years ago

5 0

A coin has 2 sides so you have a 50% chance at getting the side you choose. If you flip it 6 times you multiply 1/2 by itself 6 times.

$\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = {\boxed{\frac{1}{64}}$

Answer: $\frac{1}{64}$

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Step-by-step explanation:

The equation of the isotope decay is:

$\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }$

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$\tau \approx 8032.926\,years$

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Lastly, the relative amount is estimated by direct substitution:

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$\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }$

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2 years ago

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The p value that he got is 0.1499. This is greater than alpha = 0.05 which is the given level of significance.

If the level of significance is lesser than the p value, we would accept the null hypothesis.

Therefore, the correct option is

No, these results are not statistically significant because p>0.05

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