Answer:
y = -1/2 x - 13/2
Step-by-step explanation:
what is an equation of the line that is perpendicular to y-4=2(x-6) and passes through (-3,-5)
First, we need the slope of the given line.
y - 4 = 2(x - 6)
y - 4 = 2x - 12
y = 2x - 8
The slope of the given line is 2.
The slopes of perpendicular lines are negative reciprocals, so the slope of the perpendicular is -1/2.
y = -1/2 x + b
We use the given point as x and y and solve for b.
-5 = -1/2(-3) + b
-10 = 3 + 2b
2b = -13
b = -13/2
The equation of the perpendicular line is:
y = -1/2 x - 13/2
Set Events:
T=tests positive~T=tests negativeP=subject is pregnant~P=subject is not pregnant
We are givenP(T n ~P)=0.02P(~T n P)=0.03P(P)=0.7
recall by definition of conditional probabilityP(A|B)=P(A n B)/P(B)
Need to find P(P|~T)
First step: make a contingency diagram of probabilities (intersection, n)
P ~P sum
T 0.67 0.02 0.69=P(T)
~T 0.03 0.28 0.31=P(~T)
sum 0.70 0.30 1.00
=P(P) =P(~P)
therefore
P(P|~T)=P(P n ~T)/P(~T)=0.03/0.31 [ both read off the contingency table ]
=0.0968
Answer: 2 cars and 6 buses.
Step-by-step explanation:
x + y = 8
5x + 55y =
5 times 2 = 10
plus
55 times 6 = 330
Add 330 plus 10 = 340!
20✔️3 + 4✔️27
20✔️3 + 4✔️9 • 3
20✔️3 + 4 • 3 ✔️3
20✔️3 + 12✔️3
32✔️3.
The solution is 32✔️3.
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