Answer:
1/2 duh dummy
Step-by-step explanation:
Answer:
E
Step-by-step explanation:
-x +6 ≥ -3x - 4
Add 3x to both sides
-x + 3x + 6 ≥ -4
Combine like terms
2x + 6 ≥ -4
Subtract 6 from both side
2x ≥ -4 - 6
2x≥ -10
Divide both sides by 2
x ≥ -10/2
x ≥ -5
Answer:
Option A
Step-by-step explanation:
Option A because there is two completely different events going on, and they have nothing to do with each other.
Answer:
672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale
Step-by-step explanation:
No. of customers pass the display on the day of sale = 1462
Proportion of people will purchase if pass such a special display = 0.43
Mean = E(X)=np
E(X)=
E(X)=628.66
Standard deviation = 
Standard deviation =
Now we are supposed to find how many units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale
P(X<x)=0.01
Using z table

Hence 672.7436 units of the sale item should the store stock in order to have at most a 1 percent chance of running short of the item on the day of the sale