B. four million eighty-four thousand and nine hundred four thousandths
Answer:
w^2*(w+4)*(w^2+10)
Step-by-step explanation:
w^5+4w^4+10w^3+40w^2
w^2*(w^3+4w^2+10w+40)\w^2*(w^2*(w+4)+10(w+4))
w^2*(w+4)*(w^2+10)
Answer:
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
substitute in the formula above
We can use FOIL to solve.
(x + 7)(x + 10)
(x * x) + (x * 7) + (7 * x) + (7 * 10)
x² + 7x + 7x + 70
x² + 14x + 70
Best of Luck!
Your answer should have been 3850 in^2
1^2/5^2 = 1/25
1/25 = 154/x
1x= 154 (25)
1x/1= 3850/1
x= 3850