All categories

3 years ago

Solve the simultaneous equations -x + 5y = -7 x + y = – 5 x = 1 y= 0

Mathematics

2 answers:

vodomira [7]3 years ago

5 0

y= -5-x

-x + 5(-5-x) = -7

-x -25-5x =-7

-x-5x = 25 -7

-6x= 18

x = -3

-3 +y = -5

y= -5 +3

=-2

-(-3) + 5(-2)

3 - 10 = -7

olga_2 [115]3 years ago

4 0

Answer:

y= -2, x= -3

Step-by-step explanation:

Firstly, substitute the x and y values:

-x + 5(0)= -7

x+ 0 = -5

second thing to check: DSA - different signs addition (positive x and -x)

-x+5y=-7 take away x+y=-5

6y= -12

y= -2

To find x: -x + 5(-2)= -7

-x= -7 + 10

x= -3

You might be interested in

The figure below shows three squares whose sides form a right triangle. The areas of the two smaller squares are shown in square

mina [271]

Answer:

A:13

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A movie theater sells out all 200 seats for a midnight movie screening at $12 per ticket. The theater's total revenue that night

ss7ja [257]

It could probably be B or A

7 0

3 years ago

Read 2 more answers

A regular decagon is rotated in degrees about its center carrying the decagon onto itself. the value of n could be

lara [203]

The value of n could be 180 or 360 degrees maybe.

3 0

3 years ago

Read 2 more answers

The flag of a country contains an isosceles triangle. (Recap that an isosceles triangle contains two angles with the same measur

sesenic [268]

Answer:

30°, 30° and 120°

Step-by-step explanation:

Using the information given in the question.

let x be the measure of each congruent base angle , then

the third angle = 3x + 30

Sum the 3 angles and equate to 180

3x + 30 + x + x = 180, that is

5x + 30 = 180 ( subtract 30 from both sides )

5x = 150 ( divide both sides by 5 )

x = 30

Thus

The 2 congruent bas angles are each = 30°

The third angle = 3x + 30 = 3(30) + 30 = 90 + 30 = 120°

7 0

3 years ago

How to find (c,d,e)<br>Please do a step by step working.Thank you.

Natasha2012 [34]

(a)
The inverse is when you swap the variables and solve for y.
g(t) = 2t - 1 (Note: g(t) represents y)
rewrite as: y = 2t - 1
swap the variables: t = 2y - 1
solve for y: t + 1 = 2y
   $\frac{t + 1}{2}$ = y
Answer for (a): $g^{-1}(t)$ = $\frac{t + 1}{2}$

(b)
Same steps as part (a) above:
h(t) = 4t + 3
rewrite as: y = 4t + 3
swap the variables: t = 4y + 3
solve for y: $y =\frac{t - 3}{4}$

Answer for (b): $h^{-1}(t)$ = $\frac{t - 3}{4}$

(c)
$g^{-1} ( h^{-1}(t)) = g^{-1} (\frac{t - 3}{4})$
replace all t's in the $g^{-1}(t)$ equation with $\frac{t - 3}{4}$
$g^{-1} (\frac{t - 3}{4})$ = $\frac{ \frac{t-3}{4} + 1}{2}$
= $\frac{ \frac{t-3}{4} + \frac{4}{4}}{2}$ = $\frac{ \frac{t - 3 + 4}{4}}{2}$ = $\frac{ \frac{t + 1}{4}}{2} = \frac{t + 1}{8}$
Answer for (c): $g^{-1} ( h^{-1}(t))$ = $\frac{t + 1}{8}$

(d)
h(g(t)) = h(2t - 1) = 4(2t - 1) + 3 = 8t - 4 + 3 = 8t - 1
Answer for (d): h(g(t)) = 8t - 1

(e)
h(g(t)) = 8t - 1
   y = 8 t - 1
   t = 8y - 1
t + 1 = 8y
$\frac{t + 1}{8}$ = y
Answer for (e): inverse of h(g(t)) = $\frac{t + 1}{8}$

8 0

3 years ago