The average of the degree measures of all angles of an octagon is less than the average of the degree measures of all angles of
1 answer:
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Answer and Step-by-step explanation:
1-6
a.
What you can do is plug in 6 and start by doing the first machine first, then the second. If this doesn't work, do the second machine, then the first machine.
<em><u>The order that works is second machine, then first machine.</u></em>
<u>Second Machine:</u>
y = = 36 - 6 = 30
Plug into first machine now.
<u>First Machine:</u>
y =
We see that the result is 5.
b. <em><u>If we were to do the order of second machine, then first machine, we will never get a negative result (or -5 for that matter), due to the fact that you can't algebraically square root a negative number.</u></em>
<em><u>However, if we were to do the order of first machine, second machine, we can get a negative number. To get -5, we plug in 6 for x in the first machine, getting an answer of 1. We plug this into the second machine, getting 1^2 - 6, which results in -5.</u></em>
1-7. The absolute value of a value is the positive version of that value.
a. |54| = <em><u>54</u></em>
b. =
c. |3| - |-1| = 3 - 1 = <em><u>2</u></em>
d. |2.2 - 5.13| = |-2.93| = <em><u>2.93</u></em>
1-8.
a.
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<u>| |</u>
<u>| |</u>
<u>| |</u>
<u>| |</u>
<u>| |</u> <u> </u> <u> </u> <u> </u> <u> </u>
<u>| || || || || |</u>
<u>(5 boxes on each side)</u>
_
<u>| |</u>
<u>| |</u>
<u>| |</u>
<u>| |</u>
<u>| |</u> <u> </u> <u> </u> <u> </u> <u> </u> <u> </u>
<u>| || || || || || |</u>
<u>(6 boxes on each side)</u>
b.<em><u> The amount of squares on each side of the figure increases by 1.</u></em>
c. <em><u>There would be 1 square, because we know that the pattern is there is 2 squares added to the next figure, 1 at each end. If we go back a figure, we take away 2 squares.</u></em>
1-9.
a. -42 - 17 = <em><u>-59</u></em>
b. 8 - (-9) = 8 + 9 = <em><u>17</u></em>
c. 8(-9) = <em><u>-72</u></em>
d. -42 ÷ (-7) = <em><u>6</u></em>
e. -2(-3)(-4) = 6(-4) = <em><u>24</u></em>
f. -18 - 7 = <em><u>-25</u></em>
g. = <em><u>25</u></em>
h. = <em><u>-25</u></em>
i. = <em><u>7</u></em>
1-10. x = 2 Plug 2 in for x, then solve.
a. y = 7 - 3(2) = 7 - 6 = <em><u>1</u></em>
b. y = = 4 - 1 = <em><u>3</u></em>
c. y = = <em><u>9</u></em>
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
<em><u>I hope this helps!</u></em>
Answer:
The answer is "Option b".
Step-by-step explanation:
Calculating the common Box-Cox Transformation: