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nydimaria [60]
3 years ago
13

Write square root of −12 ​in simplest radical form.

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0

Answer:

Huh?

Step-by-step explanation:

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Write an equation of the line that has a slope of 2 and y-intercept 1 in slope-intercept form.
Vlada [557]
Y = mx + b

in this case m = 2 and b = 1 so
equation
y =2x + 1

hope this helps
4 0
3 years ago
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H(x)=3x^2+7<br> h(0)<br> help!
Angelina_Jolie [31]

Answer:

h(0) = 7

Step-by-step explanation:

by saying h(0) it is asking you to plug in 0 as the x value

3(0)^2 = 0

0 + 7 = 7

8 0
2 years ago
(-33.28 ÷ -5.2) ÷ -1.6 = ?
tigry1 [53]

Answer:

-4

Step-by-step explanation:

Use PEMDAS

5 0
3 years ago
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<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E2%20%5Cleft%28%20%5Csqrt%5B3%5D%7B%20%7Bx%7D%5E%7B2%7D%20%20%2B%20
Verizon [17]

If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

\displaystyle \int_a^b f(x) \, dx = b f(b) - a f(a) - \int_{f(a)}^{f(b)} f^{-1}(x) \, dx

Let f(x) = \sqrt{1 + x^3}. Compute the inverse:

f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}

and we immediately notice that f^{-1}(x+1)=\sqrt[3]{x^2+2x}.

So, we can write the given integral as

\displaystyle \int_0^2 f^{-1}(x+1) + f(x) \, dx

Splitting up terms and replacing x \to x-1 in the first integral, we get

\displaystyle \int_1^3 f^{-1}(x) \, dx + \int_0^2 f(x) \, dx = 2 f(2) - 0 f(0) = 2\times3+0\times1=\boxed{6}

7 0
2 years ago
PLEASE HELP WITH BOTH WILL CROWN BRAINLIEST !!!!
Korvikt [17]
41) you have a 40 day period
two visits with +75 centimeter growth each
3 visits with +6 each
in total 2*75+3*6=150+18=168
divide this by 40 days to get the average: 168/40=4.2 centimeters per day or 1.65 inches/day

42)
7x total
3x20
2x15
1x13
1x16

if you order these into a list:
13,15,15,16,20,20,20

the median is the middle value, in this case 16$
the mode is the most common value: 20$ which exists 3 times
3 0
3 years ago
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