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3 years ago

What is the total amount of gas Justin bought last week?

Mathematics

2 answers:

Lilit [14]3 years ago

4 0

Answer: 27.25

Step-by-step explanation:

I hope this helps

The answer is 27.25 because

Justin filled up his car three times a week, right?

The amount of gas he used each time are written down ( in gallons)

8.45, 13.8 and 5

You simply add these numbers together using a calculator and the answer will be 27.25

Yuliya22 [10]3 years ago

4 0

25.72 because you have to add tot he lost of the things she has for the at week

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In the diagram, MQ = QP = PO = ON. If NP is greater than MP, which must be true?

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Angle O is larger than angle QI hope this helps! ^^

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4 years ago

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Is he square root of -144 rational or irrational?

gladu [14]

Answer:

Step-by-step explanation:

Neither.

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The "i" is an imaginary representation for the square root of -1. It is a definition for sqrt(-1). So a new category of number has been created. The ancients would have been profoundly surprised to learn that such a thing existed.

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3 years ago

Find the midpoint of the line segment joining the points P1 and P2.

ludmilkaskok [199]

Formula for midpoint between two points is M(x,y)

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x=(m+0)/2=m/2 and y=(b+0)/2=b/2 M(m/2,b/2)

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3 years ago

Rita is starting a running program. The table shows the total number of miles she runs in different weeks. What is the equation

prisoha [69]

Answer:

The best fit line is $y = 1.671x + 4.699$

Step-by-step explanation:

We are given,

The table representing the number of miles run in different weeks is,

Week Miles Run

1 5

2 8

4 13

6 15

8 19

10 20

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4 years ago

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If it takes 6 hours for a plane to travel 720km with a tail wind and 8 hours to make the return trip with a head wind. Find the

denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

<u>Solution:</u>

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

$\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)$

Now at head wind → $720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)$

So, solve (1) and (2) by addition

2a = 210

a = 105

substitute a value in (1) ⇒ 105 + b = 120

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