What is the missing numerator?

Mathematics

1 answer:

mihalych1998 [28]3 years ago

7 0

Answer:

Step-by-step explanation:

(4/5)-(x/9)=6/45

6/45=(6/3)/(45/3)=2/15

4/5-(x/9)=2/15

(4/5)-(2/15)=(x/9)

(4*3)/(5*3) = 12/15

12/15-2/15=10/15

10/15=2/3

2/3=6/9

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Use the binomial expression (p+q)^n to calculate a binomial distribution with n=5 and p=0.3.(Show all steps)

Helen [10]

Answer:

The binomial in expanded form is $(0.3 + q)^{5} = \frac{243}{100000} + \frac{81}{2000}\cdot q + \frac{27}{100}\cdot q^{2} + \frac{9}{10} \cdot q^{3} + \frac{3}{2}\cdot q^{4} + q^{5}$ .

Step-by-step explanation:

The Binomial Theorem states that a binomial of the form $(a + b)^{n}$ can be expanded by using the following identity:

$(a + b)^{n} = \Sigma \limits^{n}_{k = 0}\,\frac{n!}{k!\cdot (n-k)!}\cdot a^{n-k}\cdot b^{k}$ (1)

If we know that $a = p = 0.3$ and $n = 5$ , then the expanded form of the binomial is:

$(p+q)^{n} = \frac{243}{100000} + 5\cdot \left(\frac{81}{10000} \right)\cdot q + 10\cdot \left(\frac{27}{1000})\cdot q^{2} + 10\cdot \left(\frac{9}{100} \right)\cdot q^{3} + 5\cdot \left(\frac{3}{10} \right)\cdot q^{4} + q^{5}$