Answer:
40 Apple juice and 20 Orange juice
Step-by-step explanation:
From the diagram, you know that 4 OJ makes one drink, so to make 5 drinks, you need 5 times that, or 20 OJ. You can also see that you need twice as much AJ as OJ, so that means you need 40 AJ.
*OJ = Orange juice and AJ = Apple juice
For rational functions and functions with square roots, the domain can be all real numbers except (1) anything that will make them because the square root of only non-negative values exists and that of negative values does not.
<h3>What are the domain and range of the function?</h3>
The domain of the function includes all possible x values of a function, and the range includes all possible y values of the function.
Let the functions with square roots be f(x) = √x.
The domain of this function is x ≥ 0,
Since the real number system does not exist the square root of negative numbers.
Therefore, For rational functions and functions with square roots, the domain can be all real numbers except (1) anything that will make them because the square root of only non-negative values exists and that of negative values does not.
Learn more about the domain and the range here:
brainly.com/question/21027387
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Answer and Step-by-step explanation:
We are told that AB is equal to 3x + 1.
BC is then half of AB, or 
.
AC is then 4 less than BC, or 
To find the perimeter, we add all of these together.
3x + 3x/2 + 3x/2 = 6x
1 + 1/2 + (1/2 - 4) = -2
The final answer is 6x - 2.
#teamtrees #WAP (Water And Plant)
1) No; you are incorrect. "0" is NOT a solution.
Plug in "0" for "x" ;
8*0² + 23 =? 823? ;
8*0 + 23 =? 823? ;
0 + 23 = ? 823 ? ; No! ; "0 + 23 = 23 " ; NOT "823" .
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2) The answers: x = 10, -10 ; or, write as: x = ± 10 .
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To solve:
GIven: 8x² + 23 = 823 ;
Subtract "23" from EACH SIDE of the equation:
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8x² + 23 - 23 = 823 - 23 ;
to get:
8x² = 800 ;
Now, divide EACH SIDE of the equation by "8" ;
8x² / 8 = 800 / 8 ;
to get: x² = 100 ;
Take the "square root" of EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x" ;
√(x²) = √(100) ;
x = <span>± 10 .
The answers: x = 10, -10 ; or, write as: x = </span><span>± 10 .
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