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Naddika [18.5K]
3 years ago
9

Write 4x2(–2x2 + 5x3) in standard form. Then classify it by degree and number of terms.

Mathematics
1 answer:
umka2103 [35]3 years ago
3 0
20x^5-8x^4 polynomial of the 5th degree, with two terms.

Distribute 4x^2(–2x^2 + 5x^3) to get –8x^2 + 20x^5. Reorder in standard form 20x^5-8x^4.  5 is the highest exponent so it is the 5th degree, there are two terms because terms are separated by a plus or minus.
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A cylinder soup has a radius of 1,6 in and is 5/7 in. tall what is the volume
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Answer:

V=0.0623\ inch^3

Step-by-step explanation:

Given that,

The radius of cylinder, r = 1/6 inch

The height of the cylinder, h = 5/7 inch

We need to find the volume of the cylinder. The formula for the volume of a cylinder is given by :

V=\pi r^2 h\\\\=3.14\times (\dfrac{1}{6})^2\times \dfrac{5}{7}\\\\V=0.0623\ inch^3

So, the volume of the cylinder is equal to 0.0623\ inch^3.

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According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e
slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that p = 0.09

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

So

P(X < 4) + P(X \geq 4) = 1

We want P(X \geq 4)

So

P(X \geq 4) = 1 - P(X < 4)

In which

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225

P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827

P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082

P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982

Finally

P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

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Answer:

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The second one is the only equivalent equation. Simply plug in each variable in each equation. And compare!
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