Question

The minimum turning point

Answer 1

Answer:

$y=x^2-20x+95$

Step-by-step explanation:

Write the equation in vertex form and evaluate

$y=(x-h)^2+k\\\\y=(x-10)^2-5\\\\y=x^2-20x+100-5\\\\y=x^2-20x+95$

This is because the minimum (or maximum) of a quadratic curve is its vertex and $(h,k)$ is the vertex in the formula I used