Answer:
Mass = 2.12 g
Explanation:
Given data:
Volume of KMnO₄ = 255 mL (255/1000 = 0.255 L)
Molarity = 0.0525 M
Mass in gram = ?
Solution:
First of all we will calculate the number of moles.
<em>Molarity = number of moles of solute / volume in litter</em>
0.0525 M = number of moles of solute / 0.255 L
Number of moles of solute = 0.0525 M ×0.255 L
Number of moles of solute = 0.0134 mol
Mass in gram:
<em>Number of moles = mass/ molar mass</em>
Mass = moles × molar mass
Mass = 0.0134 mol × 158.04 g/mol
Mass = 2.12 g
The agar plate with the most countable colonies should be determined by using a colony forming unit (CFU) calculator.
<h3>What is a colony?</h3>
A colony can be defined as a group of visible mass of microorganisms such as bacteria, fungi, that originated (cultured) from a single-mother cell and are grown on a solid agar medium.
In order to determine the most countable colonies, we have to count the total number of colonies by using a hemacytometer and then use a colony forming unit (CFU) calculator to determine the cfu/mL.
<u>Note:</u> You should choose a dilution factor based on the total number of colonies contained in the agar plate.
Finally, input the correct dilution factor into the colony forming unit (CFU) calculator to determine which agar plate has the most countable colonies.
Read more on dilution factor here: brainly.com/question/24881505
Answer:
PVT upon t is equal to k p is equal to k p v is equal to k p upon t is equal to K2
Explanation:
correct answer is d
