In right triangle PQR, P and Q are complementary angles. The value of sin Q is 9/41. What is the value of cos P?

Mathematics

1 answer:

evablogger [386]3 years ago

8 0

Check the picture below.

notice, in a right-triangle, there is a right-angle, thus is called a right-triangle, and the other angles are complementary angles.

notice the relation of the cosine and sine of each, in the example in the picture.

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Please explain step by step

JulijaS [17]

1. Calculate the volume of entire cube as if it was a solid rectangle:
Length x width x height=
20x16x12 = 3,940 cubic inches

2. Calculate the volume of the "missing"
Piece and subtract:
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20x8x6 = 960 cubic inches
(notice you can find the height of the missing piece by subtracting 12-6)

So your answer is 3,940-960 = 2,980 cubic inches inside the steps

6 0

3 years ago

Solve equation by factoring.

3241004551 [841]

Hi ;-)

$x^2+6x-10=30 \ \ /-30\\\\x^2+6x-40=0\\\\a=1, \ b=6, \ c=-40\\\\\Delta=b^2-4ac=6^2-4\cdot1\cdot(-40)=36+160=196\\\\\sqrt{\Delta}=\sqrt{196}=14\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-6-14}{2}=\boxed{-10}\\\\x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-6+14}{2}=\boxed4$