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2 years ago

Anyone have any idea on how to solve this

Mathematics

2 answers:

Mkey [24]2 years ago

7 0

Answer:

O y = (x + 5) (x + 3)

Step-by-step explanation:

y = (x + 4)² - 1

y = x² + 8x + 15

y = x² + 3x + 5x + 15

y = x(x + 3) + 5(x + 3)

y = (x + 5) (x + 3)

Setler79 [48]2 years ago

5 0

Answer:

Option 1 : y = ( x+5 ) ( x+3 )

Step-by-step explanation:

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Which expression is equivalent to 4(5j + 7)?

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Answer: 4(5j+7) = 20j+28

Step-by-step explanation:

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The general form of the equation we need to find is (x - h)^2 = 4p(y- k).

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3 years ago

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2 column proof is a logical argument consisting of statements and the reasons to show why those statememts are true.

Step-by-step explanation:

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3 years ago

X^2-16x+7=0 how do I solve this step by step

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3 years ago

The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and

NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

$60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120$

Let's find h with the quadratic formula:

$\fbox {Quadratic formula:} \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}$

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation

$\fbox {Pythagorean equation:}$ <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>

The base and the height are our legs. We will use "H" for the hypotenuse

$H^2 = b^2 + h^2 = 15^2 + 8^2 = 289\\ H = \sqrt {289} = 17$

H = 17

If we decrease the base and the height by 2 centimeters, we have

b' = 15 - 2 = 13 and h' = 8 - 2 = 6

With this, let's calculate the new hypotenuse:

$H'^2 = b'^2 + h'^2 = 13^2 + 6^2 = 205\\ H' = \sqrt {205} \approx 14.3$

$H' \approx 14.3$

So, the hypotenuse decreases $H - H' \approx 17 - 14.3 = 2.7$

3 0

3 years ago