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leva [86]
3 years ago
6

Write in standard form the equation of a line with a slope of -3/5 and a y intercept of -3

Mathematics
1 answer:
Vlada [557]3 years ago
7 0

Answer:

5y+3x=-9

Step-by-step explanation:

Let us start by the general form of the standard equation, Ax+By=C. One way we can solve this problem is by finding the <u>slope-intercept form</u> of this equation, y=mx+b, and converting it into the standard equation. In the slope-intercept form, m represents the slope, b represents the y intercept.

From this problem, we are given both the slope and the y intercept. We know have the equation:

y=-\frac{3}{5}x -3

Great! Now let us rearrange the terms so that the y and x terms are on one side of the equation.

y+\frac{3}{5} x=-3

This seems right, but a standard equation must have coefficient values that are real numbers. So, A and B must be real numbers. We can do this by multiplying the entire equation by 5 and ridding the denominator of the A term.

5y+3x=-9

<em>I hope this helps! Please let me know if you have any questions :)</em>

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3 years ago
76 div 4<br><br> a)15<br><br> b) 8<br><br> c) 19<br><br> d) 0<br><br> Explain
Sunny_sXe [5.5K]

Answer:

C. 19.  

Step-by-step explanation:

Let's find the answer.

Step 1:  divide the first number of 76, which is 7, by 4 and find the integer part.

7/4=1.75, so the integer part is 1.

Step 2: subtract from 7 the (integer part times 4)

7-(1*4)=3

Step 3: put toether the result (3) and the second number of 76, which is 6, so the result is 36.

Step 4: find how many times we need to add 4s to reach 36, so:

4+4+4+4+4+4+4+4+4=36 which means that:

36/4=9

Step 5: put together the two resulted numbers calculated in step 1, which is 1, and step 4, which is 9:

1 and 9 giving 19, so the answer is:

76/4=19.

In conclusion the answer is C. 19. 

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3 years ago
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Answer:

Option D (8,4)

Step-by-step explanation:

we know that

The dilation centered at the origin  (0,0) is very simple. To find out the image point multiply the scale factor to the x  and  y-coordinates of the pre-image point.

so

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